丢番图方程x3±27=14y2的整数解

摘要

With the help of the natures of odd number and even number, congruence, the Diophantine equation23x±27=14y was proved to only have trivial solution.%利用奇偶数的性质、同余的性质等证明了丢番图方程23x±27=14y仅有平凡解。