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Optical Receiver Using Noise Cancelling With an Integrated Photodiode in 40 nm CMOS Technology

机译:使用具有40 nm CMOS技术的集成光电二极管消除噪声的光接收器

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A transimpedance amplifier (TIA) based on an inverting voltage amplifier with a shunt feedback resistor using a noise cancelling technique is presented. The TIA is followed by two stages of differential limiting amplifiers and the last stage is a 50 $Omega$ differential output driver to provide an interface to the measurement setup. The TIA shows a measured optical sensitivity of $-$20.7 dBm for a BER of $10^{-9}$ using an external photodiode (PD). Another chip with the same TIA and an integrated N+/Psub PD is also introduced. The optical receiver achieves a measured transimpedance gain of 78 ${rm dB}Omega$ , 1.5 GHz bandwidth and a measured input referred noise current density of 7.2 ${rm pA}/surd{rm Hz}$ up to 1.5 GHz. The power consumption of the TIA is only 4.1 mW and the complete chip dissipates 12 mW for a single 1 V supply voltage.
机译:提出了一种基于反向电压放大器的跨阻放大器(TIA),该放大器具有使用噪声消除技术的并联反馈电阻。 TIA之后是两级差分限幅放大器,最后一级是一个50 $ Omega $ 差分输出驱动器,用于提供测量设置的接口。 TIA显示对于 $-$ 20.7 dBm tex Notation =“ TeX”> $ 10 ^ {-9} $ 使用外部光电二极管(PD)。还介绍了另一个具有相同TIA和集成N + / Psub PD的芯片。该光接收器实现了78的测量跨阻增益,公式为:1.5 GHz带宽,测量的输入参考为:{{rm dB} Omega $ 噪声电流密度高达1.5 GHz时为7.2 <公式> = {rm pA} / surd {rm Hz} $ 。 TIA的功耗仅为4.1 mW,对于单个1 V电源电压,整个芯片的功耗为12 mW。

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