首页> 外国专利> method for processing in accordance with an electric pulse code modulated in time in recurrent groups of pulses, so-called 'code, and device for implementing this process.

method for processing in accordance with an electric pulse code modulated in time in recurrent groups of pulses, so-called 'code, and device for implementing this process.

机译:用于根据在脉冲的重复组中及时调制的电脉冲代码进行处理的方法,所谓的“代码”以及用于实现该过程的设备。

摘要

659,020. Pulse code modulation circuits. LIBOIS, L. J., and GLOESS, P. F. M. July 25, 1949, No. 19559. Convention date, Aug. 5, 1948. [Class 40 (v)] Duration modulated pulses are translated into groups of binary code pulses by a succession of circuits in each of which the input pulse duration is compared with a reference time interval, a code pulse being generated if the duration of the input pulse exceeds the reference interval and a pulse of the excess duration being passed to the next circuit, while if the reference interval exceeds the input pulse duration no code pulse is generated and the input pulse is passed unchanged to the next circuit. The reference intervals in the successive circuits are each one half of that in the preceding circuit. In the embodiment described, the negative input pulse 23, Fig. 2, having a fixed leading edge and a modulated trailing edge, is inverted in valve 24, to produce pulse 28 which is fed to valve 34. It is also displaced by the reference time interval, T/2 in this case, where T is the maximum duration of the input pulses, this being effected by a delay line 25. The pulse is applied to the input 27, which is correctly terminated and is reflected from the unterminated end 26 to reappear at the input end where it is added to the pulse 28 to produce the composite pulse 32 at the grid of valve 34. As shown, the input pulse duration t is greater than T/2 so that the pulse 32 has a part 33 of greater amplitude than pulse 28 and of duration t-T/2. Valve 34 acts as a clipper passing pulse 33 to produce pulse 38 which is fed to the next coding stage input valve 70. In addition, the composite pulse 32 is fed to the control grid of pentode 39 which is cut off for the duration of the input pulse 23 by applying this pulse to its suppressor grid. The output from valve 39 is thus a pulse 41 of duration T/2 delayed by t with respect to pulse 23. The transformer 44 in the anode circuit of valve 34 inverts and differentiates the pulse 38 to produce the pair of pulses 46, 47, that corresponding to the leading edge of 38 being used to trigger a flip-flop circuit 48. The latter produces a negative pulse 50 of duration T which with the positive pulse 41, which occurs within it, is applied to the grid of valve 42. The positive pulse 41 is thus unable to unblock valve 42 to pass the input pulse 23 to the next stage, which would have occurred if it had been of less duration than T/2. The code pulse is generated by differentiating the pulse 57 on the right-hand anode of valve 48 and using the resultant leading edge pulse 61 which is fed to the mixer 64, the negative trailing edge pulse being clipped by rectifier 65. The remainder of the circuit shows a second coding stage for deriving the next digit, and pulses are shown which occur when the input pulse duration is less than T/4, the reference time interval for this stage. In this case, the composite pulse 80, corresponding to pulse 32, is unable to unblock valve 76, so that no pulse therefrom reaches the input valve 90 of the next stage. Also, the flip-flop valve 84 remains untriggered so that the pulse 86, which is a delayed version of the input pulse 38 derived from the second element of the composite pulse 80 in valve 78, is able to unbreak valve 87, to transmit pulse 89 to the next input valve 90. No code pulse is fed to the mixer 64 by the flip-flop valve 84 in the case considered. The final and nth coding stage comprises the input valve 101, Fig. 5, and a delay line 104 by which the composite pulse 107 is produced as in the other stages. As shown, the input pulse duration exceeds the reference time interval T/2n so that pulse 107 has a portion able to unblock valve 108 and produce a pulse 111 which after differentiation provides a code pulse 113 to be fed to the mixer 64. The mixer 64 consists of a delay line, to tappings on which the code pulse outputs are fed, and which are selected to time and arrange the code pulses to form a group 69 having the desired spacing and order of the pulses, which are also shaped in circuit 67.
机译:659,020。脉冲编码调制电路。 LIBOIS,LJ和GLOESS,PFM,1949年7月25日,第19559号。会议日期,1948年8月5日。[Class 40(v)]持续时间调制脉冲通过一系列电路转换成二进制代码脉冲组。将每个输入脉冲的持续时间与参考时间间隔进行比较,如果输入脉冲的持续时间超过参考间隔,则生成一个编码脉冲,并且将超过持续时间的脉冲传递到下一个电路,而如果将参考间隔超过输入脉冲持续时间,则不会生成代码脉冲,并且输入脉冲会原样传递到下一个电路。连续电路中的参考间隔分别是前一个电路中参考间隔的一半。在所述的实施例中,图2的负输入脉冲23在阀24中被反转,其具有固定的前沿和被调制的后沿,以产生脉冲28,该脉冲28被馈送到阀34。时间间隔T / 2(在这种情况下为T / 2),其中T是输入脉冲的最大持续时间,这受延迟线25的影响。该脉冲施加到输入27,该输入正确端接并从未端接的端反射在输入端重新出现图26所示的脉冲,然后将其添加到脉冲28中,以在阀34的栅格处产生复合脉冲32。如图所示,输入脉冲持续时间t大于T / 2,因此脉冲32具有一部分振幅大于脉冲28且持续时间tT / 2的33。阀34用作削波器通过脉冲33以产生脉冲38,该脉冲38被馈送到下一个编码级输入阀70。此外,复合脉冲32被馈送到五极管39的控制栅极,该栅极在该持续时间内被切断。通过将该脉冲施加到其抑制器栅极来输入脉冲23。因此,阀39的输出是持续时间T / 2的脉冲41,其相对于脉冲23延迟了t。阀34的阳极电路中的变压器44对脉冲38进行反相和微分,以产生一对脉冲46、47,...。触发电路48与触发电路48的上升沿相对应。触发电路48产生持续时间为T的负脉冲50,该负脉冲与在其内出现的正脉冲41一起施加到阀42的栅极上。因此,正脉冲41不能使阀42解除阻塞,以使输入脉冲23传递到下一级,如果持续时间小于T / 2,则会发生该情况。通过微分阀48右侧阳极上的脉冲57并使用最终的前沿脉冲61产生代码脉冲,该前沿脉冲61被馈送到混合器64,负后沿脉冲被整流器65削波。电路示出了用于导出下一位的第二编码级,并且示出了当输入脉冲持续时间小于T / 4(该级的参考时间间隔)时出现的脉冲。在这种情况下,与脉冲32相对应的复合脉冲80不能解除阀76的阻塞,因此没有脉冲到达下一级的输入阀90。而且,触发器阀84保持未触发,从而脉冲86(其是源自阀78中的复合脉冲80的第二元素的输入脉冲38的延迟版本)能够使阀87解开以传输脉冲。在这种情况下,图89中所示的信号没有被发送到下一个输入阀90。在所考虑的情况下,没有代码脉冲被触发阀84馈送到混合器64。最后的和第n个编码级包括图5的输入阀101和延迟线104,通过该延迟线104与其他级一样产生复合脉冲107。如图所示,输入脉冲持续时间超过参考时间间隔T / 2n,从而脉冲107具有能够使阀108解锁的部分并产生脉冲111,该脉冲111在微分之后提供要被馈送到混合器64的代码脉冲113。 64由延迟线组成,连接到抽头,在抽头上馈入编码脉冲输出,并选择定时以对编码脉冲进行计时和排列,以形成具有所需脉冲间隔和顺序的组69,其也在电路中成形67。

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