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首页> 外文期刊>Physical chemistry chemical physics: PCCP >Dissociations of copper(II)-containing complexes of aromatic amino acids: radical cations of tryptophan, tyrosine, and phenylalanine
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Dissociations of copper(II)-containing complexes of aromatic amino acids: radical cations of tryptophan, tyrosine, and phenylalanine

机译:含铜(II)的芳香族氨基酸配合物的解离:色氨酸,酪氨酸和苯丙氨酸的自由基阳离子

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The dissociations of two types of copper(II)-containing complexes of tryptophan (Trp), tyrosine (Tyr), or phenylalanine (Phe) are described. The first type is the bis-amino acid complex, [Cu~(II)(M)2]~(·2+), where M = Trp, Tyr, or Phe; the second [Cu~(II)(4Cl-tpy)(M)]~(·2+), where 4Cl-tpy is the tridendate ligand 4'-chloro-2,2':6',2"-terpyridine. Dissociations of the Cu(ii) bis-amino acid complexes produce abundant radical cation of the amino acid, M~(·+), and/or its secondary products By contrast, dissociations of the 4Cl-tpy-bearing ternary complexes give abundant M~(·+) only for Trp. Density functional theory (DFT) calculations show that for Tyr and Phe, amino-acid displacement reactions by H2O and CH3OH (giving [Cu~(II)(4Cl-tpy)(H2O)]~(·2+) and [Cu~(II)(4Cl-tpy)(CH3QH)]~(·2+)) are energetically more favorable than dissociative electron transfer (giving M~(·+) and [Cu~I(4Cl-tpy)]~+). The fragmentation pathway common to all these [Cu~(II)(4Cl-tpy)(M)]~(·2+) ions is the loss of NH3. DFT calculations show that the loss of NH3 proceeds via a "phenonium-type" intermediate. Dissociative electron transfer in [Cu~(II)(4Cl-tpy)(M-NH3)]~(·2+) results in [M-NH3]~(·+) . The [Phe-NH3]~(·+) ion dissociates facilely by eliminating CO2 and giving a metastable phenonium-type ion that rearranges readily into the styrene radical cation.
机译:描述了色氨酸(Trp),酪氨酸(Tyr)或苯丙氨酸(Phe)的两种类型的含铜(II)配合物的解离。第一种是双氨基酸复合物[Cu〜(II)(M)2]〜(·2 +),其中M = Trp,Tyr或Phe;第二个[Cu〜(II)(4Cl-tpy)(M)]〜(·2 +),其中4Cl-tpy是三登酸酯配体4'-氯-2,2':6',2“-吡啶。 Cu(ii)双氨基酸配合物的解离产生氨基酸,M〜(+)和/或其次级产物的大量自由基阳离子。相反,带有4Cl-tpy的三元配合物的解离产生大量M 〜(·+)仅用于Trp。密度泛函理论(DFT)计算表明,对于Tyr和Phe,H2O和CH3OH的氨基酸置换反应(产生[Cu〜(II)(4Cl-tpy)(H2O)]〜 (·2 +)和[Cu〜(II)(4Cl-tpy)(CH3QH)]〜(·2 +)在能量上比解离电子转移更有利(给予M〜(·+)和[Cu〜I(所有这些[Cu〜(II)(4Cl-tpy)(M)]〜(·2 +)离子共有的碎裂途径是NH3的损失,DFT计算表明损失是NH3经由“ phen型”中间体进行反应。[Cu〜(II)(4Cl-tpy)(M-NH3)]〜(·2 +)中的离解电子转移导致[M-NH3]〜(·+ )[Phe-NH3]〜(·+)离子通过消除容易地解离并产生亚稳的on型离子,该离子很容易重新排列成苯乙烯自由基阳离子。

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