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首页> 外文期刊>Bioresource Technology: Biomass, Bioenergy, Biowastes, Conversion Technologies, Biotransformations, Production Technologies >Use of continuous lactose fermentation for ethanol production by Kluveromyces marxianus for verification and extension of a biochemically structured model
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Use of continuous lactose fermentation for ethanol production by Kluveromyces marxianus for verification and extension of a biochemically structured model

机译:Marxianus使用连续乳糖发酵进行乙醇生产进行生物化学结构化模型的验证和延伸

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摘要

A biochemically structured model has been developed to describe the continuous fermentation of lactose to ethanol by Kluveromyces marxianus and allowed metabolic coefficients to be determined. Anaerobic lactose-limited chemostat fermentations at different dilution rates (0.02-0.35h~(-1)) were performed. Species specific rates of consumption/formation, as well as yield coefficients were determined. Ethanol yield (0.655 C-mol ethanol*C-mol lactose~(-1)) was as high as 98% of theoretical. The modeling procedure allowed calculation of maintenance coefficients for lactose consumption and ethanol production of m_s=0.6029 and m_e=0.4218 (C-mol) and (C-molh)~(-1), respectively. True yield coefficients for biomass, ethanol and glycerol production were calculated to be Y~(true) _(sx)=0.114, Y~(true) _(ex)=0.192 and Y_(sg)=2.250 (C-mol) and (C-mol)~(-1), respectively. Model calculated maintenance and true yield coefficients agreed very closely with those determined by regressions of the experimental data. The model developed provides a solid basis for the rational design of optimised fermentation of cheese whey.
机译:已经开发了一种生物化学结构化模型,以描述通过Klupromyces Marxianus的乳糖与乙醇的连续发酵,并允许确定代谢系数。在不同稀释率(0.02-0.35H〜(-1))下进行厌氧乳糖有限的化学蛋白发酵。确定物种特定的消费/形成速率,以及产量系数。乙醇产率(0.655 C-Mol乙醇* C-Mol乳糖〜(-1))高达98%的理论。施工过程允许计算乳糖消耗的维持系数和M_Ss = 0.6029和M_E = 0.4218(C-Mol)和(C-MolH)〜(-1)的乙醇产生。计算生物质,乙醇和甘油生产的真正产量系数为Y〜(TRUE)_(SX)= 0.114,Y〜(TRUE)_(EX)= 0.192和Y_(SG)= 2.250(C-MOL)和(C-Mol)〜(-1)。模型计算维护和真正的产量系数与通过实验数据的回归确定的那些非常紧密地达成了密切的。该模型为奶酪乳清的优化发酵合理设计提供了坚实的基础。

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