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The size of the largest antichain in the partition lattice

机译:分隔格中最大的反链的大小

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摘要

Consider the poset Pi(n) of partitions of an n-element set, ordered by refinement. The sizes of the various ranks within this poset are the Stirling numbers of the second kind. Let a = 1/2 - e log(2)/4. We prove the following upper bound for the ratio of the size of the largest antichain to the size of the largest rank: d(Pi(n), less than or equal to)/S(n, K-n)less than or equal to c(2)n(a)(log n)(-a-1/4), for suitable constant c(2) and n > 1. This upper bound exceeds the best known lower bound for the latter ratio by a multiplicative factor of O(1). (C) 1998 Academic Press. [References: 21]
机译:考虑n元素集的分区的位姿Pi(n),按细化排序。该位姿内各个等级的大小是第二类斯特林数。设a = 1/2-e log(2)/ 4。我们证明最大反链大小与最大秩大小之比的以下上限:d(Pi(n),小于或等于)/ S(n,Kn)小于或等于c (2)n(a)(log n)(-a-1 / 4),对于合适的常数c(2)且n>1。该上限超出了后者比率的最佳已知下限,其乘数为。 O(1)。 (C)1998年学术出版社。 [参考:21]

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