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Opposite trigonometric function arithmetical unit
Opposite trigonometric function arithmetical unit
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机译:相反三角函数算术单元
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摘要
PURPOSE:To operate an inverse trigonometric function arctan(chi) at high speed by inputting a value 1/H2+1 and a low-order digit L in a memory to a multiplier, and adding the output value of the multiplier on a value arctan(H) by an adder. CONSTITUTION:The value (chi) is divided into a high-order digit H and the low- order digit L by every (n) digits. Then, in equation I, the arctan(chi) can be obtained by one time of multiplication and that of addition by preparing a table ROM 12 which inputs H and outputs the value arctan(H) and the value 1/H2+1. Since it is H1 and L2-n, (n) digits are enough for the arithmetic accuracy of a second item in equation I. To obtain accuracy of 2n digits in the arctan (chi), it is necessary to provide an arctan(H) table of 2n digits X2n words, a 1/H2+1 table of (n)digits X 2 words, and the multiplier 14 which performs the multiplication of the output(n) digits of the 1/H2+1 table by (n) digits of L, and the adder 16 which adds the high-order (n) digits of a multiplication result on the output 2n digits of the arctan(H) table. In such a way, it is possible to operate the arctan(chi) at high speed.
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机译:目的:通过将一个值/ H <2> +1和一个低位数字L输入到乘法器中,并将乘法器的输出值加到乘法器上,以高速操作逆三角函数arctan(chi)。加法器的值arctan(H)。组成:值(chi)按每(n)个数字分为高位数字H和低位数字L。然后,在等式I中,通过准备表ROM 12,可以通过将其乘以一次并通过相加来获得arctan(chi),该表ROM 12输入H并输出值arctan(H)和值1 / H 2+ 1。因为它是H <1并且L <2 <-n>,所以(n)位对于等式I中第二项的算术精度是足够的。为了在arctan(chi)中获得2n位的精度,有必要提供2n位X2 个字的arctan(H)表,(n)位X 2个字的1 / H <2> +1表以及执行输出(n)位相乘的乘法器14将1 / H 2 +1表的L乘以(n)个数字,加法器16将相乘结果的高位(n)数字加到arctan(H)表的输出的2n个数字上。以这种方式,可以高速操作反正切(chi)。
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