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DIFFERENTIAL DIAGNOSIS METHOD FOR DETERMINING CEREBRAL-TYPE TERMINAL TYPE STATE AND MECHANICAL TRAUMA INCOMPATIBLE WITH LIFE

机译:鉴别脑型终末状态和生命不相容的机械创伤的鉴别诊断方法

摘要

FIELD: medicine.;SUBSTANCE: method involves carrying out morphologic examination of the internal organs. Macroscopic morphometric adrenal gland examination is carried out with cortical substance and medullary substance mass of each adrenal gland and ratio of cortical substance mass to medullary substance mass in the left adrenal gland being determined. In total, ratios of cortical substance mass to medullary substance mass are determined in both adrenal glands. Probability of case that is considered to belong to death group with terminal cerebral-type state of P1 type is calculated from formula P1=exp(4.34+30.08xA -30.77xB - 8.87xC - 4.18xD - 12.98xE)/(1+exp(4.34+30.08xA -30.77xB - 8.87xC - 4.18xD - 12.98xE)x100%, P2=100%-P1, where A is the ratio of cortical substance mass to medullary substance mass in the left adrenal gland, B is the ratio of cortical substance mass to medullary substance mass in both adrenal glands, C is the asymmetry coefficient of cortical substance mass, D is the asymmetry coefficient of medullary substance mass, E is the adrenal gland mass asymmetry force. C, D and E are calculated from formulas [(Dd-Ds):(Dd+Ds)]x100%, where Dd is the right parameter value and Ds is the left parameter value. If P1P2, terminal cerebral-type state is diagnosed.;EFFECT: high accuracy of diagnosis.
机译:领域:医学。;实体:方法涉及对内部器官进行形态学检查。进行宏观形态上的肾上腺检查,测定每个肾上腺的皮质物质和髓质物质质量,并确定左肾上腺的皮质物质质量与髓质物质质量之比。总的来说,在两个肾上腺中确定皮质物质质量与髓质物质质量的比率。根据公式P1 = exp(4.34 + 30.08xA -30.77xB-8.87xC-4.18xD-12.98xE)/(1 + exp)计算被认为属于P1型终末脑型状态的死亡组病例的概率(4.34 + 30.08xA -30.77xB-8.87xC-4.18xD-12.98xE)x100%,P2 = 100%-P1,其中A是左肾上腺皮质物质质量与延髓物质质量之比,B是两个肾上腺皮质物质质量与髓质质量的比值,C为皮质物质质量的不对称系数,D为髓质物质的不对称系数,E为肾上腺质量不对称力,计算C,D和E从公式[(D d -D s ):( D d + D s )] x100%,其中,D d 是右参数值,D s 是左参数值;如果P1> P2,则诊断为终末脑型状态。诊断。

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