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首页> 外文期刊>Russian Journal of Organic Chemistry >Synthesis of 2i-1-(Alkoxy-NNO-azoxy)-2-arylethenes by the Reaction of Bis(alkoxy-NNO-azoxy)methanes with Benzyl Halides under Conditions of Phase-Transfer Catalysis
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Synthesis of 2i-1-(Alkoxy-NNO-azoxy)-2-arylethenes by the Reaction of Bis(alkoxy-NNO-azoxy)methanes with Benzyl Halides under Conditions of Phase-Transfer Catalysis

机译:在相转移催化条件下双(烷氧基-NNO-偶氮氧基)甲烷与卤代苄的反应合成2i-1-(烷氧基-NNO-偶氮氧基)-2-芳烃

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摘要

Reaction of bis(methoxy- and ethoxy-NNO-azoxy)methane with benzyl halides and alkali under the conditions of a phase-transfer catalysis furnishes in one stage E-1-(alkoxy-NNO-azoxy)-2-arylethene in 21-55% yields. The intermediate products, l,l-bis(alkoxy-NNO-azoxy)-2-arylethanes under the action of alkali eliminate one of the two alkoxy-NNO-azoxy groups with the formation of a double bond. The optimum solvent is DMSO, and as benzyl halides, benzyl chlorides. In the case of 4-bromobenzyl bromide a formation was found of a side bisbenzylation product, l,3-bis(4-bromophenyl)-2,2-bis(methoxy-NNO-azoxy)propane. 10.1134/S1070428013050072
机译:在相转移催化条件下,双(甲氧基-和乙氧基-NNO-氮氧基)甲烷与苄基卤和碱的反应在21-阶段的一级E-1-(烷氧基-NNO-氮氧基)-2-芳基乙烯中进行55%的产率。中间产物,在碱的作用下的1,1-双(烷氧基-NNO-氮氧基)-2-芳基乙烷消除了两个烷氧基-NNO-氮氧基之一,形成了双键。最佳溶剂是DMSO,而苄基卤则是苄基氯。在4-溴苄基溴的情况下,发现形成双苄基化副产物1,3-双(4-溴苯基)-2,2-双(甲氧基-NNO-氮氧基)丙烷。 10.1134 / S1070428013050072

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