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Bounding the largest eigenvalue of trees in terms of the largest vertex degree

机译:以最大顶点度为界限制树的最大特征值

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Let lambda(1) (G) denote the largest eigenvalue of the adjacency matrix and let mu(1) (G) denote the largest eigenvalue of the Laplacian matrix of a graph G. It is well known that if a graph G has the largest vertex degree Deltanot equal0 then, rootDeltaless than or equal tolambda(1)(G)less than or equal toDelta and Delta+1less than or equal tomu(1)(G)less than or equal to2Delta. Thus the gap between the maximum and minimum value of lambda(1)(G) and mu(1)(G) in the class of graphs with fixed Delta is Theta(Delta). In this note we show that in the class of trees with fixed Delta this gap is just Theta(rootDelta). Namely, we show that if a tree T has the largest vertex degree Delta then lambda(1)(T)<2rootDelta-1 and mu(1)(T)
机译:令lambda(1)(G)表示邻接矩阵的最大特征值,令mu(1)(G)表示图G的拉普拉斯矩阵的最大特征值。众所周知,如果图G具有最大的特征值顶点度Deltanot不等于0,rootDelta小于或等于tolambda(1)(G)小于或等于Delta和Delta + 1小于或等于mu(1)(G)小于或等于2Delta。因此,在具有固定Delta的图类中,lambda(1)(G)和mu(1)(G)的最大值和最小值之间的差距为Theta(Delta)。在此注释中,我们显示出在具有固定Delta的树类中,此间隙仅为Theta(rootDelta)。即,我们表明如果树T具有最大的顶点度Delta,则lambda(1)(T)<2rootDelta-1和mu(1)(T)

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