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On the effective Nullstellensatz

机译:关于有效的Nullstellensatz

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Let K be an algebraically closed field and let X subset of K-m be an n-dimensional affine variety. Assume that f(1),..., f(k) are polynomials which have no common zeros on X. We estimate the degrees of polynomials A(i) is an element of K[X] such that 1 = Sigma(i=1)(k) A(i) f(i) n X. Our estimate is sharp for k <= n and nearly sharp for k > n. Now assume that f(1),..., f(k) are polynomials on X. Let I = (f(1),..., f(k)). K[X] be the ideal generated by fi. It is well-known that there is a number e(I) (the Noether exponent) such that root I-e(I) subset of I. We give a sharp estimate of e(I) in terms of n, deg X and deg f(i). We also give similar estimates in the projective case. Finally we obtain a result from the elimination theory: if f(1), ..., f(n) is an element of K[x(1),..., x(n)] is a system of polynomials with a finite number of common zeros, then we have the following optimal elimination: phi(i)(x(i)) = Sigma(j=1)(n) f(j)g(ij), i = 1,..., n, where deg f(j)g(ij) <= Pi(i=1)(n) deg f(i).
机译:令K为代数封闭场,令K-m的X子集为n维仿射变体。假设f(1),...,f(k)是在X上没有公共零的多项式。我们估计多项式的阶数A(i)是K [X]的元素,使得1 = Sigma(i = 1)(k)A(i)f(i)nX。我们对k <= n的估计是尖锐的,而对于k> n的估计是尖锐的。现在假设f(1),...,f(k)是X上的多项式。设I =(f(1),...,f(k))。 K [X]是fi生成的理想值。众所周知,存在一个数字e(I)(Noether指数),使得I的根Ie(I)子集。我们根据n,deg X和deg f给出e(I)的清晰估计。 (一世)。在投影情况下,我们也给出类似的估计。最后,我们从消除理论中得到一个结果:如果f(1),...,f(n)是K [x(1),...,x(n)]的多项式系统,则有限数量的公共零,那么我们得到以下最优消除:phi(i)(x(i))= Sigma(j = 1)(n)f(j)g(ij),i = 1。 …,n,其中deg f(j)g(ij)<= Pi(i = 1)(n)deg f(i)。

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