首页> 外文期刊>Random structures & algorithms >Learning random points from geometric graphs or orderings
【24h】

Learning random points from geometric graphs or orderings

机译:学习从几何图形或排序的随机点

获取原文
获取原文并翻译 | 示例
           

摘要

Let X-v for v is an element of V be a family of n iid uniform points in the square & xdcae;n=-n/2,n/22. Suppose first that we are given the random geometric graph G is an element of G(n,r), where vertices u and v are adjacent when the Euclidean distance d(E)(X-u,X-v) is at most r. Let n(3/14)MUCH LESS-THANrMUCH LESS-THANn(1/2). Given G (without geometric information), in polynomial time we can with high probability approximately reconstruct the hidden embedding, in the sense that "up to symmetries," for each vertex v we find a point within distance about r of X-v; that is, we find an embedding with "displacement" at most about r. Now suppose that, instead of G we are given, for each vertex v, the ordering of the other vertices by increasing Euclidean distance from v. Then, with high probability, in polynomial time we can find an embedding with displacement O(logn).
机译:设v是V的X-V是方形&xdcae中的n个IID均匀点的元素; n = -n / 2,n / 22。 首先假设我们给出了随机几何图G是G(n,r)的元素,其中顶点u和v当欧几里德距离d(e)(x-u,x-v)最多r时邻近。 让n(3/14)更小于thnrmuch distn-thnnn(1/2)。 给定的g(没有几何信息),在多项式时间中,我们可以通过高概率大致重建隐藏的嵌入,从而“达到对称”,每个顶点V的距离在X-V的距离内找到一个点; 也就是说,我们发现最多嵌入“位移”。 现在假设,对于每个顶点V,而不是G,而不是G,通过增加来自v的欧几里德距离来给予其他顶点的排序。然后,在多项式时间中,我们可以找到与位移o(logn)的嵌入。

著录项

相似文献

  • 外文文献
  • 中文文献
  • 专利
获取原文

客服邮箱:kefu@zhangqiaokeyan.com

京公网安备:11010802029741号 ICP备案号:京ICP备15016152号-6 六维联合信息科技 (北京) 有限公司©版权所有
  • 客服微信

  • 服务号