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Alcohol oxidation catalysed by Ru(VI) in the presence of alkaline hexacyanoferrate(III)

机译:Ru(VI)在碱性六氰合铁酸盐(III)存在下催化的醇氧化

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摘要

The oxidation of sodium lactate, 2-methyl-2,4-pentanediol, 2,4-butanediol, 2-butanol and 2-propanol upon treatment with alkaline hexacyanoferrate(III) using a Ru(VI) catalyst is highly effective for the oxidation of alcohols by Fe(CN)_63-. The reaction mechanism proposed involves the oxidation of the alcohol by the catalyst, a process that occurs through the formation of a substrate-catalyst complex. The decomposition of this complex yields Ru(IV) and a carbocation (owing to a hydride transfer from the α-C-H bond of the alcohol to the oxoligand of ruthenium). The role of the co-oxidant, hexacyanoferrate(III), is to regenerate the catalyst. In the oxidation reactions, the rate constants for complex decomposition and catalyst regeneration have been determined and a comparative study of the structure versus reactivity has been carried out.
机译:使用Ru(VI)催化剂用碱性六氰合铁酸盐(III)处理后的乳酸钠,2-甲基-2,4-戊二醇,2,4-丁二醇,2-丁醇和2-丙醇的氧化非常有效Fe(CN)_63-制成的醇提出的反应机理涉及通过催化剂氧化醇,该过程通过形成底物-催化剂络合物而发生。该配合物的分解产生Ru(IV)和碳正离子(由于氢化物从醇的α-C-H键转移至钌的氧配体)。助氧化剂六氰合铁酸盐(III)的作用是再生催化剂。在氧化反应中,已确定了复合物分解和催化剂再生的速率常数,并进行了结构与反应性的对比研究。

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