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Hydroxylamine electrochemistry at polycrystalline platinum in acidic media: a voltammetric, DEMS and FTIR study

机译:酸性介质中多晶铂上的羟胺电化学:伏安法,DEMS和FTIR研究

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摘要

The electrochemical activity of hydroxylamine on polycrystalline Pt in acidic media has been characterized using cyclic voltammetry, on-line differential electrochemical mass spectrometry (DEMS) and in situ FTIR. The electrochemistry of hydroxylamine (HAM) is essentially controlled by other species that interact strongly with the electrode surface. Therefore, quite moderate current densities, both in oxidation and reduction, are observed in a wide potential window between ca 0 and 1 V. The HAM electroreduction is a slow process and is masked by the Hupd. No formation of gaseous products was detected in this region; hence, ammonia must be the main product of HAM reduction. The HAM electro-oxidation is strongly influenced by the adsorption of its products, as well as their chemical transformations in solution. The key intermediate in HAM oxidation is NO, based both on voltammetric and spectroscopic evidence. Nitric oxide forms an adsorbed layer, stable over a wide potential region between ca. 0.55 and 0.75 V. At higher potentials NOads is oxidized to form (adsorbed) HNO2. At potentials above ca. 0.9 V the accumulation of HNO_2 in solution, accompanied by its partial oxidation to NO_2, is postulated. N_2O formation, observed in the potential region between ca. 0.5 and 1 V, has multiple sources. The most important source of N_2O is a homogeneous reaction between HNO_2 and HAM. The Tafel slope analysis suggests the second electron transfer to be the rate-determining step in HAM oxidation to NOads. A tentative mechanism for this reaction is proposed.
机译:使用循环伏安法,在线差分电化学质谱法(DEMS)和原位FTIR表征了羟胺对酸性介质中多晶Pt的电化学活性。羟胺(HAM)的电化学本质上受与电极表面强烈相互作用的其他物质控制。因此,在大约0至1 V的宽电位窗口中,观察到了相当适度的电流密度,包括氧化和还原。HAM电还原是一个缓慢的过程,并被Hupd掩盖。在该区域未检测到气态产物的形成;因此,氨必须是减少HAM的主要产物。 HAM的电氧化作用受其产物的吸附及其在溶液中的化学转化的强烈影响。根据伏安法和光谱学证据,HAM氧化的关键中间体是NO。一氧化氮形成一个吸附层,该吸附层在大约200到200之间的宽电位区域内稳定。 0.55和0.75V。在更高的电势下,NOads被氧化形成(吸附的)HNO2。电位高于约假定溶液中HNO_2的积累为0.9 V,并伴随其部分氧化为NO_2。 N_2O的形成,在大约200之间的电位区域中观察到。 0.5和1 V,具有多个电源。 N_2O的最重要来源是HNO_2与HAM之间的均相反应。 Tafel斜率分析表明第二次电子转移是HAM氧化为NOads的决定速率的步骤。提出了该反应的初步机制。

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