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A Polynomial Bound for Untangling Geometric Planar Graphs

机译:展开几何平面图的多项式界

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To untangle a geometric graph means to move some of the vertices so that the resulting geometric graph has no crossings. Pach and Tardos (Discrete Comput. Geom. 28(4): 585-592, 2002) asked if every n-vertex geometric planar graph can be untangled while keeping at least n(epsilon) vertices fixed. We answer this question in the affirmative with epsilon = 1/4. The previous best known bound was Omega (root log n/log log n). We also consider untangling geometric trees. It is known that every n-vertex geometric tree can be untangled while keeping at least Omega(root n) vertices fixed, while the best upper bound was O((n log n)(2/3)). We answer a question of Spillner and Wolff (http://arxiv.org/abs/0709.0170) by closing this gap for untangling trees. In particular, we show that for infinitely many values of n, there is an n-vertex geometric tree that cannot be untangled while keeping more than 3(root n - 1) vertices fixed.
机译:解开几何图形意味着移动一些顶点,以使生成的几何图形没有交叉。 Pach和Tardos(Discrete Comput。Geom。28(4):585-592,2002)询问在保持至少n(epsilon)个顶点固定的同时是否可以对每个n顶点几何平面图进行纠缠。我们以epsilon = 1/4肯定地回答这个问题。以前最知名的绑定是Omega(根日志n / log log n)。我们还考虑了几何树的纠缠。已知每一个n顶点几何树都可以进行纠缠,同时至少保持Omega(root n)顶点固定,而最佳上限是O((n log n)(2/3))。我们通过弥合树的纠缠来回答Spillner和Wolff(http://arxiv.org/abs/0709.0170)的问题。特别地,我们表明,对于n的无限多个值,存在一个n顶点几何树,当保持超过3个(根n-1)根顶点固定时,该树无法解开。

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