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The oxidation of thiosulfates with copper sulfate. Application to an industrial fixing bath

机译:用硫酸铜氧化硫代硫酸盐。应用于工业固定浴

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This paper presents the transformation of thiosulfate using Cu(II) salts, such as copper sulfate, at pH between 4 and 5. The nature and kinetics of this process were determined. In the experimental conditions employed, the reaction between thiosulfates and Cu(II) ions produces a precipitate of CuS and the remaining sulfur is oxidized to sulfate, according to the following stoichiometry: 1 mol thiosulfate reacts with 1 mol Cu~(2+)and 3 mol H_2O, generating 1 mol copper(II), 1 mol sulfate and 2 mol H_3O~+. In the kinetic study, the apparent reaction order was approx = 0 with respect to H_3O~+ concentration, in the interval 1.0 centre dot 10~(-4)-1.0 centre dot 10~(-5)M H_3O~+; of order 0.4 with respect to Cu~(2+) in the interval 0.21-0.85 g L~(-1) Cu~(2+); and of order 0 with respect to S_2O_3~(2-) in the interval 0.88-2 g L~(-1) S_2O_3~(2-). The apparent activation energy was 98 kJ mol~(-1) in the interval 15-40 deg C. On the basis of this behavior an empirical mathematical model was established, that fits well with the experimental results. The thiosulfate transformation process using copper(II) sulfate was applied to an industrial fixing bath that proceeded from the photographic industry; after this, the resulting effluent contained less than 10 mg L~(-1) of thiosulfates.
机译:本文介绍了在pH值为4到5的条件下使用Cu(II)盐(例如硫酸铜)转化硫代硫酸盐的方法。在所采用的实验条件下,根据以下化学计量,硫代硫酸盐与Cu(II)离子之间的反应生成CuS沉淀,剩余的硫被氧化成硫酸盐:1摩尔硫代硫酸盐与1摩尔Cu〜(2+)反应,然后3 mol H_2O,生成1 mol铜(II),1 mol硫酸盐和2 mol H_3O〜+。在动力学研究中,相对于H_3O〜+浓度,表观反应阶数约为= 0,在1.0中心点10〜(-4)-1.0中心点10〜(-5)M H_3O〜+之间;在0.21-0.85g L〜(-1)Cu〜(2+)的范围内,相对于Cu〜(2+)为0.4阶;且相对于S_2O_3〜(2-)为0阶,且间隔为0.88-2 g L〜(-1)S_2O_3〜(2-)。在15-40℃的温度范围内,表观活化能为98 kJ mol〜(-1)。基于此行为,建立了经验数学模型,与实验结果吻合良好。使用硫酸铜(II)的硫代硫酸盐转化工艺已应用于照相工业的工业定影浴;此后,所产生的流出物中含有少于10 mg L〜(-1)的硫代硫酸盐。

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