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Integer sequences that behave as Fibonacci-Lucas pairs

机译:表现为斐波那契-卢卡斯对的整数序列

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摘要

There have been a number of articles on the relation between the terms of the Fibonacci and Lucas sequences and how they are closely related to trigonometric and hyperbolic functions and their properties [1]. This article is based on other integer sequences. It sets out to determine other pairs of such sequences that have the same relation as the Fibonacci and Lucas have to each other. So we shall be concerned with second order recurrence relations with constant coefficients:u_n= au_(n-1) + bu _(n-2) (α, b independent of n) and pairs of sequences (u-n) and (v_n) that each satisfy it. We seek a condition that ensures the pair of sequences behave as the Fibonacci-Lucas pair behave. The tools used are entirely elementary, so in particular, no generating functions are employed. It is hoped that this makes the article suitable for students familiar with recurrences and some basic algebra. The ubiquitous Fibonacci sequence (F_n) needs little introduction [2], but its partner the Lucas sequence (L_n) is much less well known. They obey the same recurrence relation u_n = u_n-1 +u_n-2 (1) (so a = b = 1)but have different starting values The Fibonacci sequence begins, F_0 = 0, F_1 =1 and note that we adopt the convention that the first term is F_0(= 0).The Luces sequence has two different starting values, L_0 = 2,L_1 = 1. Note that two inital values and a second order recurrence|(with constant coefficients) are sufficent to define a unique sequence.
机译:关于斐波那契数列和卢卡斯数列之间的关系以及它们如何与三角函数和双曲函数及其性质密切相关的文章已有很多[1]。本文基于其他整数序列。它着手确定与斐波那契和卢卡斯彼此之间具有相同关系的其他此类序列对。因此,我们将关注具有常数系数的二阶递推关系:u_n = au_(n-1)+ bu _(n-2)(α,b独立于n)和序列对(un)和(v_n)每个人都满足。我们寻找一种条件,以确保该对序列的行为与斐波那契-卢卡斯对的行为相同。所使用的工具完全是基本工具,因此特别是不使用任何生成功能。希望这使本文适合熟悉递归和一些基本代数的学生。普适斐波那契数列(F_n)几乎不需要引入[2],但其伴侣卢卡斯数列(L_n)鲜为人知。它们遵循相同的递归关系u_n = u_n-1 + u_n-2(1)(所以a = b = 1),但是起始值不同Fibonacci序列开始,F_0 = 0,F_1 = 1,请注意,我们采用了约定第一项是F_0(= 0)。Luces序列具有两个不同的起始值L_0 = 2,L_1 =1。请注意,两个初始值和一个二阶递归|(具有恒定系数)足以定义唯一顺序。

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