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On the On-line Number of Snacks Problem

机译:零食在线数量问题

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In the number of snacks problem (NSP), which was originally proposed by our team, an on-line player is given the task of deciding how many shares of snacks his noshery should prepare each day. The on-line player must make his decision and then finish the preparation before the customers come to his noshery for the snacks; in other words, he must make decision in an on-line fashion. His goal is to minimize the competitive ratio, defined as inf_σ C_A(σ)/C_(OPT)(σ), where σ denotes a sequence of numbers of customers, C_(OPT)(σ) is the cost of satisfying a by an optimal offline algorithm, and C_A(σ) is the cost of satisfying a by an on-line algorithm. In this paper we give a competitive algorithm for on-line number of snacks problem P1, the Extreme Numbers Harmonic Algorithm (ENHA), with competitive ratio 1 + p · (M ― m)/(M + m), where M and m are two extreme numbers of customers over the total period of the game, and p is a ratio concerning the cost of the two types of situations, and then prove that this competitive ratio is the best one if an on-line player chooses a fixed number of shares of snacks for any sequence of numbers of customers. We also discuss several variants of the NSP and give some results for it. Finally, we propose a conjecture for the on-line NSP.
机译:在最初由我们的团队提出的零食数量问题(NSP)中,一个在线参与者的任务是确定他的小吃每天应该准备多少份零食。在线玩家必须做出决定,然后完成准备工作,然后顾客才能品尝小吃。换句话说,他必须以在线方式做出决定。他的目标是最小化竞争比率,定义为inf_σC_A(σ)/ C_(OPT)(σ),其中σ表示客户数量序列,C_(OPT)(σ)表示满足a最佳离线算法,而C_A(σ)是通过在线算法满足a的代价。在本文中,我们给出了一种竞争性的零食在线数量问题算法P1,极限数谐波算法(ENHA),竞争率为1 + p·(M ― m)/(M + m),其中M和m是整个游戏期间的两个极端客户数量,p是关于两种情况成本的比率,然后证明如果在线玩家选择一个固定数目,则该竞争比率是最佳比率为任意数量的客户分配的零食份额。我们还将讨论NSP的几种变体,并给出一些结果。最后,我们对在线NSP提出一个猜想。

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