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Fermentation of Peptides by Bacteroides ruminicola B14

机译:Ruminicola B14细菌对肽的发酵

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The maximum growth rate of Bacteroides ruminicola B14 was significantly improved when either Trypticase or acetate and C4-C5 fatty acids were added to defined medium containing macrominerals, microminerals, vitamins, hemin, cysteine hydrochloride, and glucose. The organism was unable to grow with peptides as the sole energy source, but growth yields from glucose were significantly improved when Trypticase was added to batch cultures containing basal medium, acetate, and C4-C5 volatile fatty acids. During periods of rapid growth, very little peptide was deaminated to ammonia, but after growth ceased there was a linear increase in ammonia. Fifteen grams of Trypticase per liter resulted in maximum ammonia production. In glucose-limited chemostats, ammonia production from peptides was inversely proportional to the dilution rate, and 87% of the variation in ammonia production could be explained by retention time in the culture vessel. Chemostats receiving Trypticase had higher theoretical maximum growth yields and lower maintenance energy expenditures than similar cultures not receiving peptide. Cells from the Trypticase cultures contained more carbohydrate, and this difference was most evident at rapid dilution rates. When corrections were made for cell composition and the amount of peptides that were fermented, it appeared that peptide carbon skeletons could be used for maintenance energy. B. ruminicola B14 was unable to grow on peptides alone because it was unable to utilize peptides at a fast enough rate to meet its maintenance requirement.
机译:当将胰蛋白酶或乙酸盐和C4-C5脂肪酸添加到含有大矿物质,微量矿物质,维生素,血红素,半胱氨酸盐酸盐和葡萄糖的特定培养基中时,金黄色拟杆菌的最大生长速率显着提高。该生物体不能以肽作为唯一能源生长,但是将胰蛋白酶加入基础培养基,乙酸盐和C4-C5挥发性脂肪酸的分批培养物中后,葡萄糖的生长产量得到了显着提高。在快速生长期间,极少的肽被脱氨为氨,但停止生长后,氨线性增加。每升15克胰蛋白酶可以产生最大的氨。在葡萄糖受限的恒化器中,从肽中产生的氨与稀释率成反比,并且可以通过在培养容器中的保留时间来解释氨产生变化的87%。与不接受肽的类似培养物相比,接受胰蛋白酶的化学稳定剂具有更高的理论最大生长量和较低的维持能量消耗。胰蛋白酶培养的细胞含有更多的碳水化合物,这种差异在快速稀释时最为明显。当对细胞组成和发酵的肽量进行校正时,看来肽碳骨架可用于维持能量。 Ruminicola B14无法单独在肽上生长,因为它无法以足够快的速率利用肽来满足其维护要求。

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