首页> 外文期刊>Case Reports in Oncology >Familial Adenomatous Polyposis in Three Generations of a Single Family: A Case Study
【24h】

Familial Adenomatous Polyposis in Three Generations of a Single Family: A Case Study

机译:家族中三代人的家族性腺瘤性息肉病:一个案例研究

获取原文
           

摘要

Background: Familial adenomatous polyposis (FAP) is an autosomal dominantly inherited syndrome characterized by the development of numerous polyps in the colon and rectum. If left untreated, the affected patients inevitably develop colon cancer by the age of 40 years. A resection of the colon (colectomy) or of the colon and rectum (proctocolectomy) is needed to minimize the risk of cancer. Case Presentation: We report a case of FAP through three generations of a single family, in which the grandmother and granddaughter underwent total colectomy with ileoanal anastomosis and did not develop colon cancer, while the son underwent subtotal colectomy with ileorectal anastomosis and developed recurrent rectal cancer. Data regarding timely surgery, surveillance, and chemoprevention are discussed. Conclusion: The FAP phenotype determines the type of treatment. In severe polyposis, proctocolectomy with ileoanal anastomosis seems to be the optimal method for minimizing the risk of cancer development. This case report advocates complete rectal removal, especially in cases of poor patient compliance with colonoscopic surveillance.
机译:背景:家族性腺瘤性息肉病(FAP)是一种常染色体显性遗传综合征,其特征是结肠和直肠中出现许多息肉。如果不加以治疗,受影响的患者将不可避免地在40岁时患上结肠癌。为了最大程度地降低癌症风险,需要切除结肠(结肠切除术)或结肠和直肠(直肠结肠切除术)。病例介绍:我们报告了一个单家族三代的FAP病例,其中祖母和孙女经历了回肠吻合术并没有发展为结肠癌,而儿子经历了回肠直肠吻合术并进行了大肠切除术,并复发了直肠癌。 。讨论了有关及时手术,监测和化学预防的数据。结论:FAP表型决定了治疗的类型。在严重息肉病中,直肠结肠切除术与回肠吻合术似乎是使癌症发展风险最小化的最佳方法。该病例报告主张完全切除直肠,尤其是在患者对结肠镜检查的依从性较差的情况下。

著录项

相似文献

  • 外文文献
  • 中文文献
  • 专利
获取原文

客服邮箱:kefu@zhangqiaokeyan.com

京公网安备:11010802029741号 ICP备案号:京ICP备15016152号-6 六维联合信息科技 (北京) 有限公司©版权所有
  • 客服微信

  • 服务号