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On the Tractability of Maximal Strip Recovery

机译:关于最大带钢回收率的可操作性

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Given two genomic maps G and H represented by a sequence of n gene markers, a strip (syntenic block) is a sequence of distinct markers of length at least two which appear as subsequences in the input maps, either directly or in reversed and negated form. The problem Maximal Strip Recovery (MSR) is to find two subsequences G' and H' of G and H, respectively, such that the total length of disjoint strips in G' and H' is maximized (or, conversely, the number of markers hence deleted, is minimized). Previously, besides some heuristic solutions, a factor-4 polynomial-time approximation is known for the MSR problem; moreover, several close variants of MSR, MSR-d (with d > 2 input maps), MSR-DU (with marker duplications) and MSR-WT (with markers weighted) are all shown to be NP-complete. Before this work, the complexity of the original MSR problem was left open. In this paper, we solve the open problem by showing that MSR is NP-complete, using a polynomial time reduction from One-in-Three 3SAT. We also solve the MSR problem and its variants exactly with FPT algorithms, i.e., showing that MSR is fixed-parameter tractable. Let k be the minimum number of markers deleted in various versions of MSR, the running time of our algorithms are O(2~(2.73k)n + n~2) for MSR, O(2~(2.73k)dn + dn~2) for MSR-d, and O(2~(5.46k)n + n~2) for MSR-DU.
机译:给定两个由n个基因标记序列表示的基因组图G和H,条带(同义区块)是长度至少为2的不同标记序列,它们在输入图中以子序列的形式出现,可以是直接序列,也可以是反向和否定形式。最大条带回收率(MSR)问题是分别找到G和H的两个子序列G'和H',以使G'和H'中不相交的条带的总长度最大(或者相反,标记的数量因此被删除)。以前,除了一些启发式解决方案之外,对于MSR问题,因子4多项式时间逼近也是众所周知的。此外,MSR,MSR-d(具有d> 2个输入图),MSR-DU(具有标记重复)和MSR-WT(具有标记加权)的几个接近变体均显示为NP完整的。在开始这项工作之前,原始的MSR问题的复杂性尚未解决。在本文中,我们通过使用三分之一的3SAT的多项式时间减少来证明MSR是NP完全的,从而解决了开放问题。我们还使用FPT算法精确地解决了MSR问题及其变体,即表明MSR是固定参数可处理的。令k为在各种版本的MSR中删除的最小标记数,对于MSR,我们的算法的运行时间为O(2〜(2.73k)n + n〜2),O(2〜(2.73k)dn + dn对于MSR-d为〜2),对于MSR-DU为O(2〜(5.46k)n + n〜2)。

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