...
首页> 外文期刊>Theoretical computer science >An improved linear kernel for complementary maximal strip recovery: Simpler and smaller
【24h】

An improved linear kernel for complementary maximal strip recovery: Simpler and smaller

机译:用于互补最大条带恢复的改进的线性核:更简单和更小

获取原文
获取原文并翻译 | 示例

摘要

We study the COMPLEMENTARY MAXIMAL STRIP RECOVERY problem (CMSR), where the given are two strings S-1 and S-2 of distinct letters, each of which appears either in the positive form or the negative form. The question is whether there are k letters whose deletion results in two matched strings. String S-1 matches string S-2 if there are partitions of S-1 and S-2 such that each component of the partitions contains at least two letters and, moreover, for each component S-1(i) of the partition of S-1, there is a unique component S-2(i); in the partition of S-2 which is either equal to S(1)(i )or can be obtained from S-1(i) by firstly reversing the order of the letters and then negating the letters. The CMSR problem is known to be NP-hard and fixed-parameter tractable with respect to k. In particular, a linear kernel of size 74k + 4 was developed based on 8 reduction rules. Very recently, by imposing 3 new reduction rules to the previous kernelization, the linear kernel has been improved to 58k. We aim to simplify the kernelization, yet obtain an improved kernel. In particular, we study 7 reduction rules which lead to a linear kernel of size 42k + 24. (C) 2018 Elsevier B.V. All rights reserved.
机译:我们研究互补的最大条带恢复问题(CMSR),其中给定是不同字母的两个串S-1和S-2,每个字符串S-1和S-2在正版或负形式中出现。问题是,是否存在删除导致两个匹配字符串的k个字母。字符串S-1匹配字符串S-2如果存在S-1和S-2的分区,使得分区的每个组件包含至少两个字母,而且,对于分区的每个组件S-1(i) S-1,有一个独特的组件S-2(i);在S-2的分区中,其等于S(1)(i)或者可以通过首先反转字母的顺序然后否定字母来从S-1(I)获得。已知CMSR问题是关于k的NP硬度和固定参数。特别地,基于8减少规则开发了大小74K + 4的线性核。最近,通过将3个新的减少规则施加到以前的内核,线性内核已得到改善为58K。我们的目标是简化内核,但获得改进的内核。特别是,我们研究了7个减少规则,导致线性内核的大小为42k + 24.(c)2018年Elsevier B.V.保留所有权利。

著录项

相似文献

  • 外文文献
  • 中文文献
  • 专利
获取原文

客服邮箱:kefu@zhangqiaokeyan.com

京公网安备:11010802029741号 ICP备案号:京ICP备15016152号-6 六维联合信息科技 (北京) 有限公司©版权所有
  • 客服微信

  • 服务号