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Adaptive Approximation in Arithmetic Circuits: A Low-Power Unsigned Divider Design

机译:算术电路的自适应近似:低功耗无符号分频器设计

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Many approximate arithmetic circuits have been proposed for high-performance and low-power applications. However, most designs are either hardware-efficient with a low accuracy or very accurate with a limited hardware saving, mostly due to the use of a static approximation. In this paper, an adaptive approximation approach is proposed for the design of a divider. In this design, division is computed by using a reduced-width divider and a shifter by adaptively pruning the input bits. Specifically, for a 2n/n division 2k/k bits are selected starting from the most significant '1' in the dividend/divisor. At the same time, redundant least significant bits (LSBs) are truncated or if the number of remaining LSBs is smaller than 2k for the dividend or k for the divisor, '0's are appended to the LSBs of the input. To avoid overflow, a 2(k + 1)/(k + 1) divider is used to compute the division of the 2k-bit dividend and the k-bit divisor, both with the most significant bits being '0'. Thus, k < n is a key variable that determines the size of the divider and the accuracy of the approximate design. Finally, an error correction circuit is proposed to recover the error caused by the shifter by using OR gates. The synthesis results in an industrial 28nm CMOS process show that the proposed 16/8 approximate divider using an 8/4 accurate divider is 2.5× as fast and consumes 34.42% of the power of the accurate 16/8 design. Compared with the other approximate dividers, the proposed design is significantly more accurate at a similar power-delay product. Moreover, simulation results show that the proposed approximate divider outperforms the other designs in two image processing applications.
机译:已经提出了许多近似算术电路,用于高性能和低功耗应用。然而,大多数设计都具有低精度或具有极限的硬件效率,并且具有有限的硬件节省,主要是由于使用静态近似。本文提出了一种自适应近似方法,用于设计分频器。在这种设计中,通过自适应地修剪输入比特,通过使用减小的宽度分频器和移位来计算划分。具体地,对于从股息/除数中的最重要的'1'开始选择2n / n划分2k / k位。同时,截断冗余最低有效位(LSB)或者如果剩余LSB的数量小于2K对于除数的分红或k,则将'0's附加到输入的LSB。为避免溢出,使用2(k + 1)/(k + 1)分频器来计算2k位股息和k位除数的划分,均具有最高的位为'0'。因此,k

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