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Many Sets Have More Sums Than Differences

机译:许多套装比差异更多的总和

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Nathanson opined [6]: "Even though there exist sets A that have more sums than differences, such sets should be rare, and it must be true with the right way of counting that the vast majority of sets satisfies |A — A| > |A +A|." The origin of this sentiment is that addition is commutative but subtraction is not — the set of sums S + S := {s_1 + s_2 : s_i ε S} of a finite set S is predisposed to be smaller than the set of differences S — S := {s_1 — s_2 : s_i ε S}. More precisely, the sizes of these two sets satisfy the bounds (1) 2ISI —1< |S +S| < 1/2 | S|~2 +1/2|S|, 2|S| —1< |S+ S|< |S|~2- |S| +1. Moreover, the sizes of S + S and S — S are correlated: both lower bounds are achieved exactly for arithmetic progressions, and if either upper bound is achieved then both are achieved (such sets are called Sidon sets). Following this reasoning, one would expect that a vanishingly small proportion of the 2~n subsets of {0, 1, 2, ...,n — 1} have more sums than differences. Our purpose, however, is to show that this
机译:Nathanson Ownined [6]:“即使存在比差异有更多的总和,这种组应该是罕见的,并且必须用正确的方式计算绝大多数套装满足的方式真实的方式 - a - a | | A + A |。“这种情绪的由来是,加法是可交换的,但减法不是 - 该组总和S + S的:= {S_1 + S_2:S_IεS}的有限集合S的预先设置成比设定差异S的小 - S:= {S_1 - S_2:S_Iεs}。更确切地说,这两组的尺寸满足界限(1)2ISI -1 <| S + S | <1/2 | S |〜2 + 1/2 | S |,2 | S | -1 <| S + S | <| S |〜2- | S | +1。此外,S + S和S-S的尺寸是相关的:算术进展的完全实现了两个下限,并且如果实现了两个上限,则实现两者(这样的组被称为Sidon集)。在此推理之后,人们希望{0,1,2,...,n - 1}的2〜n个子集的消失程度的比例比差异更多。但是,我们的目的是表明这一点

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