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Asynchronous Exploration of an Unknown Anonymous Dangerous Graph with O(l) Pebbles

机译:具有O(l)小卵石的未知匿名危险图的异步探索

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We consider the a team of asynchronous agents that must explore an unknown graph in presence of a black hole, a node which destroys all incoming agents without leaving any observable trace. Communication is achieved using pebbles that an agent can pick up, carry, and drop. It is known that, when the graph is unknown, Δ + 1 agents are necessary, and solutions exist with those many agents, using a total of O(log Δ) pebbles, where Δ is the max node degree. On the other hand, it is also known that if the agents have a map of the graph, the problem can be solved with O(1) pebbles in total, without increasing the size of the team. In this paper we address the question of whether it is possible to locate the black hole using O(1) pebbles even if the graph is unknown, and, if so, with how many agents. We first prove that with O(1) pebbles, Δ + 1 agents are not sufficient. We next prove that, regardless of the team size, 2 pebbles are not sufficient. We then show that these bounds are tight presenting a protocol that allows to locate a black hole in an unknown anonymous graph with only 3 pebbles and Δ + 2 agents.
机译:我们认为一个异步代理团队必须在存在黑洞的情况下探索未知图,黑洞是一个破坏所有传入代理而不会留下任何可观察痕迹的节点。使用卵石可以实现通信,代理可以捡起,携带和放下卵石。众所周知,当该图未知时,需要Δ+ 1个代理,并且使用总共O(logΔ)个小卵石解决了许多代理的问题,其中Δ是最大节点度。另一方面,还已知如果代理具有该图的映射,则可以使用总共O(1)个小卵石来解决问题,而无需增加团队规模。在本文中,我们解决了一个问题,即即使该图未知,是否也可以使用O(1)小卵石定位黑洞;如果是,则有多少代理人。我们首先证明,对于O(1)小卵石,Δ+ 1剂是不够的。接下来我们证明,无论团队大小,仅2个卵石都是不够的。然后,我们证明这些边界紧紧地提出了一个协议,该协议允许在只有3个小卵石和Δ+ 2代理的未知匿名图中定位黑洞。

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