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Online Scheduling on Two Uniform Machines to Minimize the Makespan with a Periodic Availability Constraint

机译:在两台统一的机器上进行在线调度,以在有周期性可用性约束的情况下最大程度地减少制造时间

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We consider the problem of online scheduling on 2 uniform machines where one machine is periodically unavailable. The problem is online in the sense that when a job presents, we have to assign it to one of the 2 uniform machines before the next one is seen. Preemption is not allowed. The objective is to minimize makespan. Assume that the speed of the periodically unavailable machine is normalized to 1, while the speed of the other one is s. Given a constant number α > 0, we also suppose that T_u = aT_a, where T_u and T_a are the length of each unavailable time period and the length of the time interval between two consecutive unavailable time periods, respectively. In the case where s ≥ 1, we show a lower bound of the competitive ratio 1 + s/1 and prove that LS algorithm is optimal. We also show that for the problem P2, MlPUonline, T_u = aT_ ∣C_(max), LS algorithm proposed in [7] is optimal with a competitive ratio 2. After that, we give some lower bounds of competitive ratio in the case 0 < s < 1. At last, we study a special case P2, MlPUonline, T_u = aT_a,non — increasing sequence∣C_(max), where non-increasing sequence means that jobs arrive in a non-increasing order of their processing times. We show that LS algorithm is optimal with a competitive ratio.
机译:我们考虑在两台统一的机器上进行在线调度的问题,其中一台机器定期不可用。从某种意义上讲,问题是在线的,当出现工作时,我们必须将其分配给2台统一的机器中的一台,然后再看到下一台。不允许抢占。目的是最小化制造时间。假设周期性不可用的机器的速度标准化为1,而另一台机器的速度为s。给定常数> 0,我们还假定T_u = aT_a,其中T_u和T_a分别是每个不可用时间段的长度和两个连续不可用时间段之间的时间间隔的长度。在s≥1的情况下,我们显示了竞争比率1 + s / 1的下限,并证明LS算法是最优的。我们还表明,对于问题P2,MlPUonline,T_u = aT_ C_(max),在[7]中提出的LS算法在竞争比为2的情况下是最优的。此后,我们给出了情况0下竞争比的下界

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