首页> 外国专利> METHOD FOR DIAGNOSING MERIDIONAL AMBLYOPIA WITH MYOPIC ASTIGMATISM IN CHILDREN

METHOD FOR DIAGNOSING MERIDIONAL AMBLYOPIA WITH MYOPIC ASTIGMATISM IN CHILDREN

机译:儿童经肌散光诊断经络性弱视的方法

摘要

FIELD: medicine. SUBSTANCE: method involves showing test objects and recording visual invoked potentials with first showing the test objects arranged as a set of black-and-white vertical strips having longitudinal axis inclined to horizontal axis and coincides with strong meridian direction of the eye affected with myopic astigmatism and having rectangular illumination intensity profile with reversion frequency distributed in time within the limits of 2-4 Hz during 2-6 min with main positive peak P100, maximum amplitude measurement following. Then, test objects arranged as a set of black-and-white horizontal strips having longitudinal axis in perpendicular relation to strong meridian direction of the eye affected with myopic astigmatism and having rectangular illumination intensity profile with reversion frequency distributed in time within the limits of 2-4 Hz during 2-6 min with main positive peak P100, maximum amplitude measurement following. Then, ratio of the main positive peak P100 maximum amplitude in the cases of the first test shown to the main positive peak P100 maximum amplitude value received when showing the second test. The ratio value being greater than 1.3, meridional amblyopia with myopic astigmatism is to be diagnosed in children. EFFECT: high accuracy of diagnosis. 4 dwg
机译:领域:医学。实质:该方法涉及显示测试对象并记录视觉调用的电位,首先显示测试对象为一组黑白垂直条,其纵向轴倾斜于水平轴,并且与受近视散光影响的眼睛的强子午线方向重合并具有矩形照明强度分布图,其反转频率在2-6分钟内在2-4 Hz的范围内及时分布,并具有主正峰值P 100 ,随后是最大幅度测量。然后,将测试对象布置为一组黑白水平条,其纵轴与受近视散光影响的眼睛的强子午线方向垂直相关,并且具有矩形照度分布,其回复频率随时间分布在2的范围内在2-6分钟内为-4 Hz,主正峰值为P 100 ,随后为最大振幅测量。然后,在显示第一个测试的情况下,主正峰值P 100 最大振幅与在显示第二个测试时所接收的主正峰P 100 最大振幅之比。该比值大于1.3,即要诊断儿童子午弱视伴近视散光。效果:诊断准确性高。 4 dwg

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