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PARITY PREDICTION CIRCUIT FOR FULL ADDER

机译:全价的奇偶校验预测电路

摘要

PPROBLEM TO BE SOLVED: To construct a parity prediction circuit of a full adder from a small number of inputs and a small number of elements. PSOLUTION: The parity prediction circuit has computing units, each with a first selector which receives the inputs of carry four parity CP [k-1, 0] and CP [k-1, 1] when carry-in Cin=0 and 1 (k is an integer of not more than n) and which outputs either the input CP [k-1, 0] or CP [k-1, 1] as a carry four parity cp [k, 0] according to a generation bit g[k-2] resulting from addition inputs A[k-2] and B[k-2], and a second selector which receives the inputs of the carry four parity CP [k-1, 0] and CP [k-1, 1] and which outputs either the input CP [k-1, 0] or CP [k-1, 1] as an inverted signal of the carry four parity cp [k, 1] according to a propagation bit p [k-2] resulting from the addition inputs A[k-2] and B[k-2]. The computing units are interconnected in a plurality of rows, and either the carry four parity cp [n, 0] or cp [n, 1] is output as a carry four parity CPn according to the carry in Cin at the final selector. PCOPYRIGHT: (C)2004,JPO&NCIPI
机译:

要解决的问题:用少量的输入和少量的元件构成一个全加法器的奇偶校验预测电路。

解决方案:奇偶校验预测电路具有计算单元,每个计算单元都有一个第一选择器,当进位Cin = 0时,该选择器接收进位四个奇偶校验CP [k-1,0]和CP [k-1,1]的输入和1(k是不大于n的整数),并根据a来输出输入CP [k-1,0]或CP [k-1,1]作为进位四奇偶校验cp [k,0]由加法输入A [k-2]和B [k-2]产生的生成位g [k-2],以及第二选择器,该选择器接收进位四个奇偶校验CP [k-1,0]和CP [ k-1,1],并根据传播位p输出输入CP [k-1,0]或CP [k-1,1]作为进位四个奇偶校验cp [k,1]的反相信号由相加输入A [k-2]和B [k-2]得出的[k-2]。计算单元以多行互连,并且根据最终选择器中的进位Cin,将进位四奇偶校验cp [n,0]或cp [n,1]输出为进位四奇偶校验CPn。

版权:(C)2004,日本特许厅和日本国家唱片公司

著录项

  • 公开/公告号JP2004234110A

    专利类型

  • 公开/公告日2004-08-19

    原文格式PDF

  • 申请/专利权人 FUJITSU LTD;

    申请/专利号JP20030019036

  • 发明设计人 IKE ATSUSHI;

    申请日2003-01-28

  • 分类号G06F7/38;G06F11/10;

  • 国家 JP

  • 入库时间 2022-08-21 23:34:45

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