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Austenitic Stainless steel with High Mn and N

机译:高锰高氮奥氏体不锈钢

摘要

An austenitic stainless steel with high contents of Mn and N is provided to suppress generation of nitrogen pores using a numerical formula considering the degree of influence of nitrogen and formation behavior of delta ferrite on solid solubility in steel by reciprocally controlling compositions ratios of alloy elements. An austenitic stainless steel with high contents of Mn and N comprises, by weight percent, 0.15% or less of C, 1.0% or less of Si, 5 to 12% of Mn, 8.0% or less of Ni, 14.0 to 23.0% of Cr, 0.40% or less of N and 3.0% or less of Cu with the balance being Fe and other unavoidable elements, wherein constituents of an alloy is controlled such that a ratio of a Cr equivalent(Creq.) to a Ni equivalent(Nieq.) and an excess nitrogen index(Ex.N) satisfy the following numerical formula: A1ÎEx.N+A2ÎCreq.=1(A1:0.2351, A2:0.4015). The excess nitrogen index satisfies the following numerical formula: Ex.N={N/(Cr+0.5Mn-C-0.5Si-0.05Ni)}Î100. The Ni equivalent and the Cr equivalent satisfy the following numerical formulas: Nieq.(Ni equivalent)=Ni+0.25Mn+15N+25C+0.35Cu, and Creq.(Cr equivalent)=Cr+0.7Si.
机译:提供一种Mn和N含量高的奥氏体不锈钢,通过使用数值公式,通过相互控制合金元素的组成比,考虑到氮的影响程度和δ铁素体的形成行为对钢中的固溶度,使用数值公式来抑制氮孔的产生。 Mn和N含量高的奥氏体不锈钢包括按重量百分比计的C:0.15%或以下; Si:1.0%或以下; Mn:5-12%; Ni:8.0%以下; Ni:14.0-23.0% Cr,N的0.40%以下,Cu的3.0%以下,其余为Fe和其他不可避免的元素,其中,控制合金的成分以使Cr当量(Creq。)与Ni当量(Nieq)的比例)和过量氮指数(Ex.N)满足以下数值公式:A1ÎEx.N+ A2Creq。<= 1(A1:0.2351,A2:0.4015)。过量氮指数满足以下数值公式:Ex.N = {N /(Cr + 0.5Mn-C-0.5Si-0.05Ni)} 100。 Ni当量和Cr当量满足以下数值公式:Nieq。(Ni当量)= Ni + 0.25Mn + 15N + 25C + 0.35Cu,Creq。(Cr当量)= Cr + 0.7Si。

著录项

  • 公开/公告号KR100641577B1

    专利类型

  • 公开/公告日2006-10-31

    原文格式PDF

  • 申请/专利权人

    申请/专利号KR20050032304

  • 发明设计人 이종석;김영환;채동철;

    申请日2005-04-19

  • 分类号C22C38/38;C22C38/40;C22C38/18;

  • 国家 KR

  • 入库时间 2022-08-21 21:22:42

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