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In the annular optical resonator mirror of the annular

机译:在环形光学谐振腔中的环形

摘要

PROBLEM TO BE SOLVED: To easily extract a laser beam to the outside of a mirror by providing a slit on an electron orbital plane to drive an electron beam from the exterior, and forming an optical resonator so that the electromagnetic field mode generated in the optical resonator is not affected by the slit. ;SOLUTION: A barrel type optical resonator 1 is provided with a slit 2. The cylindrical coordinates (r, z) of the cross sectional shape of the barrel type optical resonator 1 are formed into a circular arc shape of r=ρ2/R+√ (R02-z2) or a parabolic shape of r=R-z2/(4R0), where ρ: electron orbit radius, R: radius of the barrel type optical resonator 1 on an electron orbit plane, R0=Rsin2θ, and cosθ=ρ/R. The intensity of the electromagnetic field becomes maximum on the electron orbit when the cross sectional shape (r) is the circular arc shape or the parabolic shape. The energy of the electromagnetic field is dispersed on the face of the barrel type optical resonator 1. Even when the slit 2 is opened at the center section of the barrel type optical resonator 1, it gives little effect.;COPYRIGHT: (C)2000,JPO
机译:解决的问题:通过在电子轨道平面上提供一个狭缝以从外部驱动电子束,并形成一个光学谐振器,以便在光学系统中产生电磁场模式,可以轻松地将激光束引到反射镜的外部。谐振器不受缝隙的影响。 ;解决方案:桶型光谐振器1上有一个缝2。桶型光谐振器1的横截面形状的圆柱坐标(r,z)形成为r = rho2 /的圆弧形。 R +√ (R02-z2)或抛物线形状为r = R-z2 /(4R0),其中:ρ:电子轨道半径,R:桶形光学谐振器1在电子轨道平面上的半径,R0 =Rsin2θ,并且costheta == rho / R。当横截面形状(r)为圆弧形或抛物线形时,电磁场的强度在电子轨道上变为最大。电磁场的能量分散在桶型光学谐振器1的表面上。即使在桶型光学谐振器1的中央部分开有缝隙2,其影响也很小。;版权所有:(C)2000 ,日本特许厅

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