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METHOD OF DIAGNOSING DISORDERS OF SEXUAL DEVELOPMENT IN CHILDREN

机译:诊断儿童性发育障碍的方法

摘要

FIELD: medicine.;SUBSTANCE: invention relates to medicine, namely to child's age andrology, and is intended for diagnostics of disorders of sexual development in boys. Simultaneous ultrasonic examination of prostate gland and gonads is performed. Total volume of gonads and volume of prostate gland are determined. Coefficient of ratio of total volume of gonads to volume of prostate gland is calculated by formula C=Vpg/Vg tot., where C is ratio coefficient, Vpg is volume of prostate gland, Vg tot is total volume of gonads. It is compared with standard coefficient, equal 1.6-2.0. If value C≤1.6, conclusion about reduction of volume of gonads with respect to prostate gland - hypogonadism, or increase of volume of prostate gland because of inflammatory of volume processes - is made, and disorder of sexual development is diagnosed. If value C≥2.0, conclusion about underdevelopment of prostate gland, or about increase of gonads in case of tumout or inflammatory process is made and disorder of sexual development is diagnosed.;EFFECT: method makes it possible to carry out accurate and early diagnostics of sexual development disorders in boys.;2 ex
机译:技术领域本发明涉及医学,即涉及儿童的年龄男科学,并且旨在诊断男孩的性发育障碍。同时对前列腺和性腺进行超声检查。确定性腺的总体积和前列腺的体积。用公式C = Vpg / Vg tot计算性腺总体积与前列腺体积之比的系数,其中C为比率系数,Vpg为前列腺体积,Vg tot为性腺总体积。将其与标准系数(等于1.6-2.0)进行比较。如果值C≤1.6,则得出关于前列腺的性腺体积减少-性腺功能减退或由于体积过程的炎症引起的前列腺体积增加的结论,并且诊断出性发育障碍。如果C值≥2.0,则得出有关前列腺发育不足或发生肿瘤或炎症过程时性腺增加并诊断出性发育障碍的结论;效果:该方法可以对前列腺癌进行准确的早期诊断男孩的性发育障碍。; 2前

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