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Manufacturing Processes of bis (Phthalimide) s and polieterimidas, and bis (Phthalimide) s and Polieterimidas formed from the same

机译:双(邻苯二甲酰亚胺)和聚丙烯酸酯的制造工艺,以及由它们组成的双(邻苯二甲酰亚胺)和多胺酯的生产工艺

摘要

Procedure for the manufacture of a Composition of bis (Phthalimide)Understanding the procedure imidaciu00f3n catalyze a substituted PHTHALIC ANHYDRIDE and diamine with an organic Catalyst, in the presence of a Solvent,And The Catalyst of Quaternary ammonium salts, Quaternary phosphonium salts, salts of guanidinium salts, Pyridinium, imidazolium salts,And their combinations; in which the PHTHALIC ANHYDRIDE replaced presents a formula * * * * and the diamine Organic formula gives a formula H2n - R - NH2; to provide the composition of bis (Phthalimide)Comprising a residue of Catalyst, and a bis (Phthalimide) of the formula in the formula * * * +, in the above formulae, X is selected from Fluorine, Chlorine, Bromine, iodine, Nitro,And their combinations, and R is selected from an aromatic hydrocarbon group which has 6 to 27 carbon ATOMS, a Halogenated Derivative of the sameA group of linear or branched chain alquileno presents 2 to 10 carbon ATOMS, a Halogenated Derivative of the same, a Group cicloalquileno presents 3 to 20 carbon Atoms.Halogenated Derivative of a (-, - c6h10) Z, where z is an integer from 1 to 4, which presents a rest of hidrocarbilo Aromatic Aromatic groups 1 to 6,A divalent Group and the formula formula * * * * that Q1 is a member selected from the group of a simple Link, - O -, - S -, - C (o) -, - and - SO2 -, -, - cyh2y,Where is an integer from 1 to 5, and their combinations; The conversion in the bis (Phthalimide) is completed by 99%, on the basis of the moles of the substituted PHTHALIC ANHYDRIDE,In less than 6 hours, and the bis (Phthalimide) comprises less than or equal to 0.5 percent in moles of PHTHALIC ANHYDRIDE replaced residualAnd less than or equal to 2 percent in moles of Mao, on the basis of the total moles of substituted PHTHALIC ANHYDRIDE, Organic diamine, and a monofunctional reactant, if used.
机译:双(邻苯二甲酰亚胺)组合物的制备方法理解在溶剂存在下,咪唑胺催化取代的邻苯二甲酸酐和二胺与有机催化剂的反应,以及季铵盐,季phospho盐,盐的催化剂胍盐,吡啶鎓,咪唑鎓盐及其组合;其中被取代的邻苯二甲酸酐具有式* * * *和二胺有机化合物具有式H 2n-R-NH 2;提供由催化剂残基和式* * * +组成的双(邻苯二甲酰亚胺)的组成,在上式中,X选自氟,氯,溴,碘,硝基,以及它们的组合,并且R选自具有6至27个碳原子的ATOMS的芳族烃基,相同的卤代衍生物基团的直链或支链alquileno呈现2至10个碳原子的ATOMS,相同的卤代基, cicloalquileno组具有3至20个碳原子。(-,-c6h10)Z的卤代衍生物,其中z为1至4的整数,代表其余的1到6的Hidrocarbilo芳族芳族基团,一个二价基团和公式* * * * Q1是从简单链接组中选择的成员--O-,-S-,-C(o)-,-和-SO2-,-,-cyh2y,其中1至5,及其组合;基于取代的邻苯二甲酸酐的摩尔数,双(邻苯二甲酰亚胺)的转化率在不到6小时内完成了99%,并且双(邻苯二甲酰亚胺)的邻苯二酚的摩尔含量小于或等于0.5%以取代的邻苯二甲酸酐,有机二胺和单官能反应物(如果使用)的总摩尔数为基准,用酸酐代替残留物的摩尔数应小于或等于2%。

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