首页> 外文OA文献 >Rebuttal to “Discussion of ‘Second law analysis of reverse osmosis desalination plants: An alternative design using pressure retarded osmosis’ Energy 2011 36: 6617–6626”
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Rebuttal to “Discussion of ‘Second law analysis of reverse osmosis desalination plants: An alternative design using pressure retarded osmosis’ Energy 2011 36: 6617–6626”

机译:反驳“讨论反渗透海水淡化厂的第二定律分析:使用减压渗透的替代设计”Energy 2011 36:6617-6626“

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摘要

We have had several conversations with Knutson during recent months, and we certainly agree that the one-dimensional mass exchanger model is more appropriate than the zero-dimensional model which has appeared in much of the past literature and which we also applied. We have been working on revisions of these calculations that incorporate the one-dimensional model, and we report some of our findings in Refs. [2] ; [5]. However, we believe that PRO has clear potential for energy recovery, as we explain in detail below. Further, Knutson's analysis of the power generation is flawed and his conclusions regarding energy recovery are not accurate.Knutson's method of analysis makes the assumption of infinite membrane water permeability (equivalent to infinite surface area), taking the value of A in Eq. (1) to be infinity. Because the value of A for the membrane is assumed to be infinite, the local water flux is equal to zero at the inlet, outlet, or both ends of the PRO module. In another words, the driving force for the water flux will vanish at the inlet, outlet, or both ends. This is similar to the assumption of zero pinch at the end of a heat exchanger, such as might be obtained with infinite surface area. This is an interesting method, and it should give similar trends as given in Ref. [4] if it is applied correctly.
机译:在最近几个月中,我们与Knutson进行了多次对话,我们当然同意一维质量交换模型比过去很多文献中出现的零维模型更合适,并且我们也应用了零维模型。我们一直在对包含一维模型的这些计算进行修订,并在参考资料中报告了我们的一些发现。 [2]; [5]。但是,我们相信PRO具有明显的能量回收潜力,如下文详细解释。此外,克努特森(Knutson)对发电的分析是有缺陷的,并且他关于能量回收的结论也不准确。克努特森(Knutson)的分析方法假设膜的透水率是无限的(等于无限大的表面积),取等式中的A值。 (1)要无限。因为膜的A值被假定为无穷大,所以PRO模块的入口,出口或两端的局部水通量等于零。换句话说,水通量的驱动力将在入口,出口或两端消失。这类似于热交换器末端零压的假设,例如可以用无限大的表面积获得。这是一种有趣的方法,它应具有与参考资料中给出的趋势类似的趋势。 [4]如果正确应用。

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