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The roles of halides in the acetaminophen degradation by UV/H2O2 treatment : kinetics, mechanisms, and products analysis

机译:卤化物在UV / H2O2处理中对乙酰氨基酚降解中的作用:动力学,机理和产物分析

摘要

This study evaluated the effects of halide ions (chloride and bromide) on the degradation of acetaminophen, a widely used drug, with the UV/H2O2 advanced oxidation treatment. Chloride showed minimal effects on the acetaminophen degradation, whereas increasing bromide concentration reduced the degradation rate because bromide promoted the formation of Br2 -, which had a lower reaction rate than OH. Interestingly, acetaminophen degradation was enhanced when both chloride and bromide were present in the solution. This was probably attributed to the high yield of ClBr- radicals predicted by using the Kintecus model. Additional tests using five model compounds (4-chlorophenol, 4-methoxyphenol, 4-hydroxylbenzoic acid, 17β-estradiol, and bisphenol A) suggested that ClBr- radicals selectively reacted with electron-rich moieties of the organic pollutants. In the presence of natural organic matter (NOM), increasing concentration of chloride or bromide reduced the degradation rate of acetaminophen. In contrast, with a constant concentration of co-existing chloride, the acetaminophen degradation was promoted by increasing bromide concentration. The product analysis showed that the HO. and halide radicals resulted in different pathways of acetaminophen degradation. The HO. radicals favored electrophilic aromatic substitution at the ortho and para positions, forming the -OH substituted acetaminophen, whereas halide radicals preferentially led to one-electron oxidation and formation of phenoxyl radicals as intermediates. These results highlight the multiple roles of salinity in water and wastewater treatment. In addition to acting as HO. scavengers, halogen radicals may significantly contribute to the organics degradation via their high selectivity towards electron-rich moieties. The resultant intermediate products require further toxicity assessment.
机译:这项研究评估了卤素离子(氯化物和溴化物)对乙酰氨基酚(一种广泛使用的药物)的降解作用,并采用了UV / H2O2高级氧化处理。氯化物对对乙酰氨基酚的降解几乎没有影响,而增加溴化物的浓度则降低了降解速率,因为溴化物促进了Br2-的形成,其反应速率低于OH。有趣的是,溶液中同时存在氯化物和溴化物时,对乙酰氨基酚的降解作用会增强。这可能归因于使用Kintecus模型预测的ClBr自由基的高收率。使用五个模型化合物(4-氯苯酚,4-甲氧基苯酚,4-羟基苯甲酸,17β-雌二醇和双酚A)进行的其他测试表明,ClBr-自由基与有机污染物的富电子部分选择性反应。在天然有机物(NOM)的存在下,氯化物或溴化物浓度的增加会降低对乙酰氨基酚的降解率。相反,在恒定浓度的共存氯化物下,对乙酰氨基酚的降解通过增加溴化物浓度来促进。产品分析表明HO。卤化物自由基导致对乙酰氨基酚降解的不同途径。 HO。自由基有利于在邻位和对位进行亲电芳族取代,形成-OH取代的对乙酰氨基酚,而卤化物自由基优先导致单电子氧化并形成苯氧基自由基作为中间体。这些结果突出了盐度在水和废水处理中的多重作用。除了充当HO。清除剂,卤素自由基可能通过其对富电子部分的高选择性而大大促进有机物的降解。所得中间产物需要进一步的毒性评估。

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