In this paper, we consider the problem about finding out perfect powers in analternating sum of consecutive cubes. More precisely, we completely solve theDiophantine equation $(x+1)^3 - (x+2)^3 + cdots - (x + 2d)^3 + (x + 2d + 1)^3= z^p$, where $p$ is prime and $x,d,z$ are integers with $1 leq d leq 50$.
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机译：在本文中，我们考虑了在分析连续立方体的分析之和中找到完美权力的问题。更确切地说，我们完全解决了杀药线方程$（x + 1）^ 3 - （x + 2）^ 3 + cdots - （x + 2d）^ 3 +（x + 2d + 1）^ 3 = z ^ p $ ，其中$ p $是prime和$ x，d，z $是一个满$ 1 leq d leq 50 $的整数。
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