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首页> 外文期刊>Pediatrics: Official Publication of the American Academy of Pediatrics >Breastfeeding and reduced risk of sudden infant death syndrome: a meta-analysis.
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Breastfeeding and reduced risk of sudden infant death syndrome: a meta-analysis.

机译:母乳喂养和降低婴儿猝死综合症的风险:一项荟萃分析。

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CONTEXT: Benefits of breastfeeding include lower risk of postneonatal mortality. However, it is unclear whether breastfeeding specifically lowers sudden infant death syndrome (SIDS) risk, because study results have been conflicting. OBJECTIVE: To perform a meta-analysis to measure the association between breastfeeding and SIDS. METHODS: We identified 288 studies with data on breastfeeding and SIDS through a Medline search (1966-2009), review articles, and meta-analyses. Twenty-four original case-control studies were identified that provided data on the relationship between breastfeeding and SIDS risk. Two teams of 2 reviewers evaluated study quality according to preset criteria; 6 studies were excluded, which resulted in 18 studies for analysis. Univariable and multivariable odds ratios were extracted. A summary odds ratio (SOR) was calculated for the odds ratios by using the fixed-effect and random-effect inverse-variance methods of meta-analysis. The Breslow-Day test for heterogeneity was performed. RESULTS: For infants who received any amount of breast milk for any duration, the univariable SOR was 0.40 (95% confidence interval [CI]: 0.35-0.44), and the multivariable SOR was 0.55 (95% CI: 0.44-0.69). For any breastfeeding at 2 months of age or older, the univariable SOR was 0.38 (95% CI: 0.27-0.54). The univariable SOR for exclusive breastfeeding of any duration was 0.27 (95% CI: 0.24-0.31). CONCLUSIONS: Breastfeeding is protective against SIDS, and this effect is stronger when breastfeeding is exclusive. The recommendation to breastfeed infants should be included with other SIDS risk-reduction messages to both reduce the risk of SIDS and promote breastfeeding for its many other infant and maternal health benefits.
机译:背景:母乳喂养的益处包括降低新生儿后死亡的风险。但是,尚不清楚母乳喂养是否能特别降低婴儿猝死综合症(SIDS)的风险,因为研究结果存在矛盾。目的:进行荟萃分析以测量母乳喂养与小岛屿发展中国家之间的联系。方法:我们通过Medline搜索(1966-2009年),评论文章和荟萃分析,确定了288项包含母乳喂养和SIDS数据的研究。确定了24项原始病例对照研究,这些研究提供了母乳喂养与SIDS风险之间关系的数据。由2名审稿人组成的两个小组根据预设标准评估研究质量;排除了6个研究,导致18个研究进行了分析。提取单变量和多变量比值比。通过使用荟萃分析的固定效应和随机效应反方差方法,计算了优势比的汇总优势比(SOR)。进行了Breslow-Day异质性测试。结果:对于在任何持续时间内接受任何量母乳的婴儿,单变量SOR为0.40(95%置信区间[CI]:0.35-0.44),多变量SOR为0.55(95%CI:0.44-0.69)。对于任何2个月或更大的母乳喂养,单变量SOR为0.38(95%CI:0.27-0.54)。在任何时间进行纯母乳喂养的单变量SOR为0.27(95%CI:0.24-0.31)。结论:母乳喂养对小岛屿发展中国家有保护作用,仅母乳喂养时这种作用更强。对母乳喂养婴儿的建议应与其他降低小岛屿发展中国家风险的信息一起纳入,以降低小岛屿发展中国家的风险并促进母乳喂养为其其他许多母婴健康带来好处。

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