首页> 外文期刊>Russian Journal of Organic Chemistry >Tandem Transformations of Bromo-Substituted β-(Methylsulfonyl)styrenes in Reactions with Dimethyl Malonate, Methyl Cyanoacetate, and Methyl Acetoacetate
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Tandem Transformations of Bromo-Substituted β-(Methylsulfonyl)styrenes in Reactions with Dimethyl Malonate, Methyl Cyanoacetate, and Methyl Acetoacetate

机译:丙二酸二甲酯,氰基乙酸甲酯和乙酰乙酸甲酯与溴代β-(甲基磺酰基)苯乙烯的串联转化

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摘要

β-Bromo-β-(methylsulfonyl)styrene reacted with dimethyl malonate and methyl cyanoacetate in the presence of sodium hydride to give sulfonyl-substituted cyclopropanes, and sulfonyl-substituted 2,3-dihydro-furan was also formed in the reaction with methyl acetoacetate. Reactions of α-bromo-β-(bromomethylsul-fonyl)styrene with dimethyl malonate and methyl cyanoacetate led to the formation of 2,3-dihydro-λ~6-thio-phene S,S-dioxide derivatives. In the reaction of a-bromo-β-(bromomethylsulfonyl)styrene with methyl acetoacetate, 2,3-dihydro-λ~6-thiophene 5,5-dioxide and 2,5-dihydro-λ~6-thiophene S,S-dioxide derivatives and methyl acetoacetate O-alkylation product, methyl 3-[(E)-2-(bromomethylsulfonyl)-1-phenylvinyloxy]but-2-enoate, were obtained at a ratio of 2.7:1.2:1. α-Bromo-β-(methylsulfonyl)styrene reacted with dimethyl malonate to produce dimethyl 2-[2-(methylsulfonyl)-1-phenylethylidene]malonate. The reaction of β-bromo-β-(bromo-methylsulfonyl)styrene with dimethyl malonate and methyl cyanoacetate were strictly stereoselective, and they afforded tetrahydro-λ~6-thiophene S,S-dioxide derivatives. The reaction of the same substituted styrene with methyl acetoacetate was not stereoselective, and the products were two diastereoisomeric tetrahydro-λ~6-thio-phene S,S-dioxides and sulfonyl-substituted 2,3-dihydrofuran at a ratio of 2.3:2.7:1.
机译:在氢化钠存在下,β-溴-β-(甲基磺酰基)苯乙烯与丙二酸二甲酯和氰基乙酸甲酯反应,生成磺酰基取代的环丙烷,在与乙酰乙酸甲酯的反应中也生成磺酰基取代的2,3-二氢呋喃。 。 α-溴-β-(溴甲基磺酰甲酰基)苯乙烯与丙二酸二甲酯和氰基乙酸甲酯的反应导致形成2,3-二氢-λ〜6-硫代苯硫醚,S-二氧化物衍生物。在a-溴-β-(溴甲基磺酰基)苯乙烯与乙酰乙酸甲酯的反应中,2,3-二氢-λ〜6-噻吩5,5-二氧化物和2,5-二氢-λ〜6-噻吩S,S-以2.7:1.2:1的比例获得了二氧化碳衍生物和乙酰乙酸甲酯的O-烷基化产物3-[((E)-2-(溴甲基磺酰基)-1-苯基乙烯基氧基]丁-2-烯酸甲酯。 α-溴-β-(甲基磺酰基)苯乙烯与丙二酸二甲酯反应,生成2- [2-(甲基磺酰基)-1-苯乙叉基]丙二酸二甲酯。 β-溴-β-(溴-甲基磺酰基)苯乙烯与丙二酸二甲酯和氰基乙酸甲酯的反应是严格立体选择性的,它们提供了四氢-λ〜6-噻吩S,S-二氧化物衍生物。相同取代的苯乙烯与乙酰乙酸甲酯的反应不是立体选择性的,产物为两种非对映异构体四氢-λ〜6-噻吩二氧化物S,S-二氧化物和磺酰基取代的2,3-二氢呋喃,比率为2.3:2.7 :1。

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