首页> 外文期刊>Russian Journal of General Chemistry >Reactions of S-Trimethylstannyl and S-(3-Trimethylstannyl-propyl) Derivatives of 1,5-Pentanedithiol with N,4-Dichlorobenzenesulfonamide Sodium Salt
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Reactions of S-Trimethylstannyl and S-(3-Trimethylstannyl-propyl) Derivatives of 1,5-Pentanedithiol with N,4-Dichlorobenzenesulfonamide Sodium Salt

机译:1,5-戊二硫酚的S-三甲基锡烷基和S-(3-三甲基锡烷基-丙基)衍生物与N,4-二氯苯磺酰胺钠盐的反应

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摘要

Difunctional derivatives of 1,5-pentanedithiol, 1,5-bis(trimethylstannylthio)pentane (CH_2)_5(SSnR_3)_2 and 1,5-bis(3-trimethylstannylpropylthio)pentane (CH_2)_5[S(CH_2)-3SnR_3]_2 (R = Me), differ by mutual arrangement of the tin and sulfur atoms and therefore react differently with N.4-dichlorobenzenesulfonamide sodium salt ArSO_2N(Na)Cl (Ar = 4-lC_6H-40. The first of these substrates possesses two direct Sn-S bonds which are cleaved by the action of 2 equiv of 4-ClC_6H_4SO_2N(Na)Cl (desulfurization). The resulting pentamethylenedithiobis-sulfonamide (CH_2)-5[SN(SnMe_3)SO_2Ar]_2 undergoes oxidative imination of both S(II) atoms with additional 2 equiv of 4-ClC_6H_4SO_2N(Na)Cl to afford sulfinimidamide derivative (CH_2)-5[S=NSO_2Ar)N(SnR_3)SO_2Ar]_2. By contrast, both pairs of the sulfur and tin atoms in the bissulfide (CH_2)_5[S(CH_2)_3SnR_3]_2 are separated by a trimethylene bridge, and this substrate reacts with 2 equiv of 4-ClC_6H_4SO_2N(Na)Cl to form tin-containing bis-sulfimide (CH_2)_5[S(=NSO_2Ar)(CH_2)_3SnR_3]_2. According to the ~1H and ~13C NMR data, interaction between two pairs of the tin and sulfur atoms at both ends of the bis-sulfimide molecule gives the to independent sterically favorable coordination rings.
机译:1,5-戊二硫酚,1,5-双(三甲基锡烷基硫基)戊烷(CH_2)_5(SSnR_3)_2和1,5-双(3-三甲基锡烷基丙基硫基)戊烷(CH_2)_5 [S(CH_2)-3SnR_3]的双官能衍生物_2(R = Me),由于锡和硫原子的相互排列而异,因此与N.4-二氯苯磺酰胺钠盐ArSO_2N(Na)Cl(Ar = 4-lC_6H-40。反应不同。第一个底物具有两个直接的Sn-S键被2当量的4-ClC_6H_4SO_2N(Na)Cl作用裂解(脱硫)。生成的五亚甲基二硫代双磺酰胺(CH_2)-5 [SN(SnMe_3)SO_2Ar] _2均被两个S氧化氧化(II)具有另外2当量的4-ClC_6H_4SO_2N(Na)Cl原子,得到亚磺酰胺衍生物(CH_2)-5 [S = NSO_2Ar] N(SnR_3)SO_2Ar] _2。相比之下,双硫化物(CH_2)_5 [S(CH_2)_3SnR_3] _2中的硫和锡原子对都被三亚甲基桥隔开,并且该底物与2当量的4-ClC_6H_4SO_2N(Na)Cl反应形成含锡双硫酰亚胺(CH_2)_5 [S(= NSO_2Ar)(CH_2)_3SnR_3] _2。根据〜1H和〜13C NMR数据,双硫酰亚胺分子两端的两对锡和硫原子之间的相互作用产生独立的空间有利配位环。

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