...
首页> 外文期刊>Radiation Physics and Chemistry >The influence of radical transfer and scavenger materials in various concentrations on the gamma radiolysis of phenol
【24h】

The influence of radical transfer and scavenger materials in various concentrations on the gamma radiolysis of phenol

机译:自由基转移和清除剂材料在不同浓度下对苯酚γ分解的影响

获取原文
获取原文并翻译 | 示例
           

摘要

The influence of a radical scavenger (tert-butanol (t-BuOH)) and two radical transfer materials (formic acid (HCOOH) and formate anion (HCOO-)) on the radical set during radiolysis of a simple model compound, phenol (PhOH, 1.0 x 10(-4) mol L-1) is discussed in this study. PhOH solutions were irradiated with gamma-rays, in the presence of 1.0 x 10(-3), 5.0 x 10(-2) and 5.0 x 10(-1) mol L-1 t-BuOH, HCOOH or HCOONa under deoxygenated and O-2-saturated reaction conditions. The rate of transformation of PhOH increased significantly in the presence of dissolved O-2. The radical transfer or scavenger materials used reduced the rates of transformation of PhOH in O-2-saturated solutions to a similar degree. The simultaneous presence of O-2 and the organic additives in excess proportionally to PhOH results in the conversion of the radical set to less reactive intermediates (t-(OOBuOH)-O-center dot, HO2 center dot or O-2(center dot-)), which made minor contribution to the transformation of PhOH. Under oxygenated conditions, t-BuOH and HCOOH in low concentrations slightly promoted the degradation, as opposed to HCOO- which reduced it. However, using higher additive concentrations, their competitive reactions for the primary intermediates came into prominence, thus they reduced the efficiency of PhOH decomposition. HO2 center dot and O-2(center dot-), and also the carbon-centred radicals formed (order of their reactivity t-(BuOH)-Bu-center dot >(COOH)-C-center dot > CO2 center dot-) have only a minor contribution to the degradation of PhOH, and the reactions of (OH)-O-center dot+PhOH and e(aq)(-) +PhOH are the significant processes. (C) 2015 Elsevier Ltd. All rights reserved.
机译:自由基清除剂(叔丁醇(t-BuOH))和两种自由基转移物质(甲酸(HCOOH)和甲酸根阴离子(HCOO-))对简单模型化合物苯酚(PhOH)辐射分解过程中自由基的影响,1.0 x 10(-4)mol L-1)在此研究中进行了讨论。在脱氧的条件下,在1.0 x 10(-3),5.0 x 10(-2)和5.0 x 10(-1)mol L-1 t-BuOH,HCOOH或HCOONa的存在下,用γ射线照射PhOH溶液。 O-2-饱和反应条件。在溶解的O-2存在下,PhOH的转化率显着增加。所使用的自由基转移或清除剂材料将O-2-饱和溶液中PhOH的转化速率降低了相似程度。 O-2和有机添加剂的同时存在与PhOH成正比,导致自由基转变为反应性较低的中间体(t-(OOBuOH)-O-中心点,HO2中心点或O-2(中心点) -)),对PhOH的转化贡献不大。在含氧条件下,低浓度的t-BuOH和HCOOH稍微促进了降解,而HCOO-则降低了降解。但是,使用较高的添加剂浓度,它们对主要中间体的竞争反应突出,因此降低了PhOH的分解效率。 HO2中心点和O-2(中心点),还形成了以碳为中心的自由基(它们的反应性顺序t-(BuOH)-Bu-中心点>(COOH)-C-中心点> CO2中心- )对PhOH的降解只有很小的贡献,(OH)-O-中心点+ PhOH和e(aq)(-)+ PhOH的反应是重要的过程。 (C)2015 Elsevier Ltd.保留所有权利。

著录项

相似文献

  • 外文文献
  • 中文文献
  • 专利
获取原文

客服邮箱:kefu@zhangqiaokeyan.com

京公网安备:11010802029741号 ICP备案号:京ICP备15016152号-6 六维联合信息科技 (北京) 有限公司©版权所有
  • 客服微信

  • 服务号