首页> 外文期刊>Mathematical logic quarterly: MLQ >A Hanf number for saturation and omission: the superstable case
【24h】

A Hanf number for saturation and omission: the superstable case

机译:饱和和遗漏的Hanf数:超稳定情况

获取原文
获取原文并翻译 | 示例
           

摘要

Suppose t = (T, T_1, p) is a triple of two theories in vocabularies τ ? τ_1 with cardinality λ, T ? T_1 and a τ_1-type p over the empty set that is consistent with T_1. We consider the Hanf number for the property "there is a model M_1 of T_1 which omits p, but M_1τ is saturated". In [2], we showed that this Hanf number is essentially equal to the L?wenheim number of second order logic. In this paper, we show that if T is superstable, then the Hanf number is less than _((2~((2λ)+)))~+.
机译:假设t =(T,T_1,p)是词汇τ中两个理论的三倍。 τ_1的基数为λ,T? T_1和与T_1一致的空集上的τ_1类型p。我们考虑属性的Hanf数“有一个T_1的模型M_1忽略了p,但是M_1τ是饱和的”。在[2]中,我们证明了这个汉夫数基本上等于二阶逻辑的李文海姆数。在本文中,我们证明如果T是超稳定的,则Hanf数小于_((2〜(((2λ)+)))〜+。

著录项

相似文献

  • 外文文献
  • 中文文献
  • 专利
获取原文

客服邮箱:kefu@zhangqiaokeyan.com

京公网安备:11010802029741号 ICP备案号:京ICP备15016152号-6 六维联合信息科技 (北京) 有限公司©版权所有
  • 客服微信

  • 服务号