首页> 外文期刊>Inorganic Chemistry: A Research Journal that Includes Bioinorganic, Catalytic, Organometallic, Solid-State, and Synthetic Chemistry and Reaction Dynamics >Metal complexes of N-benzamidoporphyrin: (N-benzimido-meso-tetraphenylporphyrinato) (methanol)zinc(II) methanol solvate and (acetato)(N-benzamido-meso-tetraphenylporphyrinato)cadmium(II) benzene solvate
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Metal complexes of N-benzamidoporphyrin: (N-benzimido-meso-tetraphenylporphyrinato) (methanol)zinc(II) methanol solvate and (acetato)(N-benzamido-meso-tetraphenylporphyrinato)cadmium(II) benzene solvate

机译:N-苯甲酰胺卟啉的金属配合物:(N-苯甲酰胺基-间-四苯基卟啉酮)(甲醇)锌(II)甲醇溶剂化物和(乙酰基)(N-苯甲酰胺基-间-四苯基卟啉酮)镉(II)苯溶剂化物

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The crystal structures of N-benzamido-meso-tetraphenylporphyrin (NHCOC6H5-Htpp; 1), (N-benzimido-meso-tetraphenylporphyrinato)(methanol)zinc(II) [Zn(N-NCOC6H5-tPP)(MeOH); 2(MeOH)], and (acetato)(N-benzamido-meso-tetraphenylporphyrinato)cadmium(II) [Cd(N-NHCOC6H5-tpp)(OAc); 3] were established. The coordination sphere around Zn2+ ion in 2(MeOH) is a distorted trigonal bipyramid with N(2), N(5), and 0(2) lying in the equatorial plane, whereas, for Cd2+ ion in 3, it is a sitting-atop derivative with a distorted trigonal bipyramidal geometry in which the apical site is occupied by atoms N(2) and 0(2). Cd in 3 acquires five-coordination with five strong bonds [Cd(l)N(1) = 2.319(5) Angstrom, Cd(l)-N(2) = 2.252(5) Angstrom, Cd(l)-N(3) = 2.332(5) Angstrom, Cd(l)-O(2) = 2.292(5) Angstrom, and Cd(l)0(3) = 2.317(5) Angstrom] and with one secondary intramolecular interaction [Cd(l)...N(4)]. The porphyrin ring in these two complexes is distorted to a large extent. The plane of the three pyrrole nitrogen atoms [i.e., N(l)-N(3)] strongly bonded to Zn2+ in 2(MeOH) and to Cd2+ in 3 is adopted as a reference plane 3N. For the Zn2+ complex, the pyrrole nitrogen bonded to the benzamido (BA) ligand lies in a plane with a dihedral angle of 33.8degrees with respect to the 3N plane, but for the Cd2+ complex, this dihedral angle is found to be 31.4degrees. In the former complex, Zn2+ and N(5) are located on the different side at -0.08 and 1.39 Angstrom from its 3N plane, and in the latter one, Cd2+ and N(5) are also located on the different side at 1.08 and -1.51 Angstrom from its 3N plane. VT NMR (H-1 and C-13) studies of 3 show that the acetate acts as a bidentate ligand and the OAc- exchange does not occur in CD2Cl2. Moreover, the NH proton [i.e., H(5)] of 3 in CD2Cl2 is observed as a sharp singlet at delta = -1.13 ppm with Deltanu(1/2) = 4 Hz at 20 degreesC indicating that the intermolecular proton exchange between water and NH proton is rapid. [References: 28]
机译:N-苯甲酰胺基-间-四苯基卟啉(NHCOC6H5-Htpp; 1),(N-苯甲酰胺基-间-四苯基卟啉对)(甲醇)锌(II)[Zn(N-NCOC6H5-tPP)(MeOH); 2(MeOH)]和(乙酰基)(N-苯甲酰胺基-间-四苯基卟啉基)镉(II)[Cd(N-NHCOC6H5-tpp)(OAc); 3]建立。 2(MeOH)中Zn2 +离子周围的配位球是扭曲的三角双锥体,其中N(2),N(5)和0(2)位于赤道平面,而对于3中的Cd2 +离子,它是一个坐位-具有扭曲的三角双锥体几何形状的-atop导数,其中顶端位置被原子N(2)和0(2)占据。 3中的Cd具有五个强键的五配位[Cd(l)N(1)= 2.319(5)埃,Cd(l)-N(2)= 2.252(5)埃,Cd(l)-N( 3)= 2.332(5)埃,Cd(l)-O(2)= 2.292(5)埃,Cd(l)0(3)= 2.317(5)埃],并且具有一个次级分子内相互作用[Cd( l)... N(4)]。这两个复合物中的卟啉环在很大程度上变形。将与2(MeOH)中的Zn 2+和3中的Cd 2+牢固结合的三个吡咯氮原子的平面[即,N(1)-N(3)]作为参考平面3N。对于Zn2 +络合物,与苯甲酰胺(BA)配体结合的吡咯氮位于一个相对于3N平面二面角为33.8度的平面中,但是对于Cd2 +络合物而言,该二面角为31.4度。在前一种络合物中,Zn2 +和N(5)位于距其3N平面-0.08和1.39埃的另一侧,而在后一种络合物中,Cd2 +和N(5)也位于1.08和3.85埃的另一侧。从3N平面起-1.51埃。 3的VT NMR(H-1和C-13)研究表明,乙酸盐起着双齿配体的作用,而OAc交换在CD2Cl2中不发生。此外,在20°C时Deltanu(1/2)= 4 Hz时,在delta = -1.13 ppm处观察到CD2Cl2中3的NH质子[即H(5)]为尖峰单峰,表明水之间的分子间质子交换NH质子很快[参考:28]

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