...
首页> 外文期刊>Applied mathematics and computation >ND-agent scheduling of linear-deteriorating tasks with positional due indices to minimize total completion time and maximum cost
【24h】

ND-agent scheduling of linear-deteriorating tasks with positional due indices to minimize total completion time and maximum cost

机译:ND-Agent调度与位置到期索引的线性恶化任务,以最小化总完成时间和最大成本

获取原文
获取原文并翻译 | 示例
           

摘要

This paper investigates the ND-agent scheduling of linear-deteriorating tasks on a single machine with positional due indices. Under the ND-agent setting, there are two agents A and B and each agent X is an element of {A, B} has its set of tasks T-(X), called X-tasks. Moreover, ND-agent means that T-(A) and T((B) )are allowed to be non-disjoint, which is a generalization of the traditional two-agent setting. Each task has a linear-deteriorating processing time and a positional due index. In this paper, we consider two problems: The first problem is to find a feasible schedule which minimizes the total completion time of the A-tasks under the condition that the maximum cost of the B-tasks is bounded by a threshold value. The second problem is the Pareto scheduling problem to minimize the total completion time of the A-tasks and the maximum cost of the B-tasks, simultaneously. We show in this paper that the two problems are solvable in O(n(2)) time and in O(n(4)) time, respectively. If the maximum cost of the tasks of agent B is restricted to some lateness-like criteria, for the version without the positional restriction, the time complexity for solving the above two problems can be reduced to O(nlog n) and O(n(3)log n), respectively. Our research includes a new technique for calculating the number of non-dominated points. (C) 2019 Elsevier Inc. All rights reserved.
机译:本文调查了在具有位置到期索引的单个机器上线性恶化任务的ND-Agent调度。在ND-Agent设置下,有两个代理A和B,每个代理x是{a,b}的元素,其组件为t-(x),称为x-tasks。此外,ND-Agent意味着允许T-(a)和t((b))不分相位,这是传统的双剂设置的概括。每个任务具有线性恶化处理时间和位置到期指标。在本文中,我们考虑了两个问题:第一个问题是找到一个可行的时间表,该时间表最小化A-任务的总完成时间在B-TASK的最大成本受到阈值的情况下。第二个问题是Pareto调度问题,以尽量减少A-任务的总完成时间和同时B-TASK的最大成本。我们在本文中展示了两个问题,分别在O(n(2))时间和O(n(4))时间内溶解。如果代理B的任务的最大成本仅限于某些迟到的标准,则对于没有位置限制的版本,可以将上述两个问题解决的时间复杂度还原为O(nlog n)和o(n( 3)分别为log n)。我们的研究包括一种计算非主导点数的新技术。 (c)2019 Elsevier Inc.保留所有权利。

著录项

相似文献

  • 外文文献
  • 中文文献
  • 专利
获取原文

客服邮箱:kefu@zhangqiaokeyan.com

京公网安备:11010802029741号 ICP备案号:京ICP备15016152号-6 六维联合信息科技 (北京) 有限公司©版权所有
  • 客服微信

  • 服务号