...
首页> 外文期刊>ACM transactions on algorithms >On the complexity of approximating a nash equilibrium
【24h】

On the complexity of approximating a nash equilibrium

机译:关于逼近纳什均衡的复杂性

获取原文
获取原文并翻译 | 示例

摘要

We show that computing a relatively (i.e., multiplicatively as opposed to additively) approximate Nash equilibrium in two-player games is PPAD-complete, even for constant values of the approximation. Our result is the first constant inapproximability result for Nash equilibrium, since the original results on the computational complexity of the problem [Daskalakis et al. 2006a; Chen and Deng 2006]. Moreover, it provides an apparent-assuming that PPAD is not contained in TIME(n~(O(log n)))-dichotomy between the complexities of additive and relative approximations, as for constant values of additive approximation a quasi-polynomialtime algorithm is known [Lipton et al. 2003]. Such a dichotomy does not exist for values of the approximation that scale inverse-polynomially with the size of the game, where both relative and additive approximations are PPAD-complete [Chen et al. 2006]. As a byproduct, our proof shows that (unconditionally) the sparsesupport lemma [Lipton et al. 2003] cannot be extended to relative notions of constant approximation.
机译:我们证明了,即使对于近似值的恒定值,在两人游戏中计算相对(即乘性而不是相加)的近似Nash平衡也是PPAD完全的。我们的结果是Nash平衡的第一个常数不可逼近结果,因为有关该问题的计算复杂度的原始结果[Daskalakis等。 2006年a; [Chen and Deng 2006]。此外,它提供了一个明显的假设,即在加法复杂度和相对逼近之间的TIME(n〜(O(log n)))-二分法中不包含PPAD,因为对于加法逼近的常数,准多项式时间算法是已知的[Lipton等。 2003]。这样的二分法不存在与博弈规模成反比多项式缩放的近似值,其中相对近似和加法近似都是PPAD完全的[Chen等。 2006]。作为副产品,我们的证明表明(无条件)稀疏支持引理[Lipton等。 [2003年]无法扩展为常数近似的相对概念。

著录项

相似文献

  • 外文文献
  • 中文文献
  • 专利
获取原文

客服邮箱:kefu@zhangqiaokeyan.com

京公网安备:11010802029741号 ICP备案号:京ICP备15016152号-6 六维联合信息科技 (北京) 有限公司©版权所有
  • 客服微信

  • 服务号