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The role of electronegativity on the extent of nitridation of group 5 metals as revealed by reactions of tantalum cluster cations with ammonia molecules

机译:电负性对第5组金属氮化程度的作用,如钽聚类阳离子与氨分子的反应所揭示的

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Reactions of the free tantalum cation, Ta+, and tantalum cluster cations, Ta-n(+) (n = 2-10), with ammonia are presented. The reaction of the monomer cation, Ta+, with two molecules of NH3 leads to the formation of TaN2H2+ along with release of two H-2 molecules. The dehydrogenation occurs until the formal oxidation number of the tantalum atom reaches +5. On the other hand, all the tantalum cluster cations, Ta-n(+), react with two molecules of NH3 and form TanN2+ with the release of three H-2 molecules. Further exposure to ammonia showed that TanNmH+ and TanNm+ are produced through successive reactions; a pure nitride and three H-2 molecules are formed for every other NH3 molecule. The nitridation occurred until the formal oxidation number of the tantalum atoms reaches +5 as in the case of TaN2H2+ in contrast to other group 5 elements, i.e., vanadium and niobium, which have been reported to produce nitrides with lower oxidation states. The present results on small gas-phase metal-nitride clusters show correlation with their bulk properties: tantalum is known to form bulk nitrides in the oxidation states of either +5 (Ta3N5) or +3 (TaN), whereas vanadium and niobium form nitrides in the oxidation state of +3 (VN and NbN). Along with DFT calculations, these findings reveal that nitridation is driven by the electron-donating ability of group 5 elements, i.e., electronegativity of the metal plays a key role in determining the composition of the metal nitrides.
机译:提供了自由钽,TA +和钽簇阳离子,TA-N(+)(n = 2-10)的反应,具有氨。单体阳离子Ta +的反应,具有两种NH 3分子导致Tan2H2 +的形成以及释放两个H-2分子。发生脱氢,直到钽原子的正式氧化数达到+5。另一方面,所有钽簇阳离子,Ta-N(+),与两个NH 3分子反应,并通过释放三个H-2分子形成Tann2 +。进一步暴露于氨表明,TannMH +和Tannm +通过连续反应产生;为每个其他NH 3分子形成纯氮化物和三个H-2分子。氮化发生,直到钽原子的正式氧化数达到+ 5,如Tan2H2 +与其他组5元素相比,即钒和铌,这据报道,钒和铌产生具有较低氧化态的氮化物。小型气相金属 - 氮化物簇的目前结果显示出与堆积性质的相关性:已知钽在+ 5(Ta3N5)或+3(TAN)的氧化态中形成大量氮化物,而钒和铌形成氮化物在+ 3(VN和NBN)的氧化状态。随着DFT计算,这些发现表明,氮化是由第5组元素的电子捐赠能力驱动的,即金属的电负性在确定金属氮化物的组合物中起着关键作用。

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