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What is the ground electronic state of KO?

机译:KO的接地电子状态是什么?

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High-level, restricted coupled cluster with singles, doubles, and perturbative triples calculations are performed to determine the ground electronic state of KO. In the absence of spin-orbit coupling, we find that the ground state is a (2)Sigma(+) state, with a (2)Pi state lying just over 200 cm(-1) higher in energy. We ascertain that basis set extension, higher-order correlation energy, mass-velocity, and Darwin relativistic terms do not change this ordering. We then calculate the low-lying Omega states when spin-orbit coupling is turned on. The (2)Sigma(1/2)(+) state undergoes an avoided crossing with the (2)Pi(1/2) state, and we therefore designate the ground state as X-1/2. This state is essentially (2)Sigma(1/2)(+) at short R, but essentially (2)Pi(1/2) at long R; there is a corresponding A 1/2 state with the opposite behavior. These states have significantly different shapes and so spectroscopy from the adiabatic states. Finally, we calculate the dissociation energy D-0, of KO as 66 +/- 1 kcal mol(-1) and derive DeltaH(f) (KO, 0 K) as 13.66 +/- 1 kcal mol(-1). (C) 2002 American Institute of Physics. [References: 48]
机译:执行具有单打,双打和微扰三重计算的高级受限耦合簇,以确定KO的地面电子状态。在没有自旋轨道耦合的情况下,我们发现基态是(2)Sigma(+)状态,而(2)Pi状态的能量高出200 cm(-1)以上。我们确定基集扩展,高阶相关能量,质量速度和达尔文相对论项不会改变此顺序。然后,当自旋轨道耦合打开时,我们将计算低洼的Omega状态。 (2)Sigma(1/2)(+)状态避免与(2)Pi(1/2)状态交叉,因此我们将基态指定为X-1 / 2。此状态在短R时基本上是(2)Sigma(1/2)(+),但在长R时基本上是(2)Pi(1/2);对应的A 1/2状态具有相反的行为。这些状态具有明显不同的形状,因此光谱与绝热状态不同。最后,我们将KO的离解能D-0计算为66 +/- 1 kcal mol(-1),得出DeltaH(f)(KO,0 K)为13.66 +/- 1 kcal mol(-1)。 (C)2002美国物理研究所。 [参考:48]

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