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Kinetics of Methanolysis of Substituted Benzamide O-(Phenoxycarbonyl)- and O-(Alkoxycarbonyl)Oximes Catalyzed by Sodium Methanolate

机译:甲醇钠催化的苯甲酰胺O-(苯氧羰基)-和O-(烷氧羰基)肟的甲醇分解动力学

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The kinetics of methanolysis of substituted benzamide O-(phenoxycarbonyl)- and O-(alkoxycarbonyl)oximes catalyzed by sodium methanolate was studied at 25 deg C. THe reaction proceeds in two steps. In the first, faster step, the substituted phenoxy group is exchanged for a methoxy group giving rise to substituted O-(methoxycarbonyl)oximes. In the second step, a benzamide oxime is eliminated and dimethyl carbonate is formed. The slope of the plot of the rate constant in dependence on the sodium methanolate concentration has an increasing tendency in both steps. In the presence of 18-crown-6, the plots are linear and the rate constants are lower than in the absence of the crown ether. The rate constants of the reaction of the substrate with the methanolate ion and with the MeONa ion pair were determined assuming that the sodium cation-catalyzed reactions constitute the rate-determining step of the reaction of the substrate with the MeONa ion pair. For the elimination of the aryloxy group and of the substituted benzamide oxime, the rate constants of the reaction with the ion pair are roughly twelvefold and twentyfold higher, respectively, than in the uncatalyzed reaction. The slope of the dependence of log #kappa# on the pK_a of the substituted phenols (#beta#_lg) has the value of -0.52 for the uncatalyzed reaction of elimination of the substituted phenoxy group, -0.83 for the elimination of the benzamide oxime group, and -0.53 for the reaction with the ion pair. In the first step and probably also in the second step, the reaction proceeds by the concerted mechanism. The relatively high #rho# value of methanolysis of substituted benzamide O-(4-nitrophenoxycarbonyl)oximes, 0.63, suggests that the structure of the transition state approaches that of the tetrahedral intermediate.
机译:在25℃下研究了由甲醇钠催化的取代的苯甲酰胺O-(苯氧羰基)-和O-(烷氧羰基)肟的甲醇分解动力学。该反应分两步进行。在第一步中,较快的步骤是将取代的苯氧基交换为甲氧基,从而产生取代的O-(甲氧基羰基)肟。在第二步中,除去苯甲酰胺肟,形成碳酸二甲酯。速率常数随甲醇钠浓度的变化曲线在两个步骤中都有增加的趋势。在存在18冠6的情况下,该图是线性的,并且速率常数低于没有冠醚的情况。假定钠阳离子催化的反应构成了底物与MeONa离子对的反应的速率决定步骤,确定了底物与甲醇根离子和与MeONa离子对的反应速率常数。为了消除芳氧基和取代的苯甲酰胺肟,与离子对的反应速率常数分别比未催化反应高约十二倍和二十倍。 log#kappa#对取代苯酚(#beta#_lg)的pK_a的依赖性的斜率对于未催化的取代苯氧基消除反应为-0.52,对于消除苯甲酰胺肟为-0.83。基,-0.53用于与离子对的反应。在第一步中,也可能在第二步中,反应通过协同机制进行。取代的苯甲酰胺O-(4-硝基苯氧基羰基)肟的甲醇分解的相对较高的#rho#值为0.63,表明过渡态的结构接近四面体中间体的结构。

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