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Why has nature invented three stop codons of DNA and only one start codon?

机译:自然界为什么发明了三个终止密码子和一个起始密码子?

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We examine the standard genetic code with three stop codons. Assuming that the synchronization period of length 3 in DNA or RNA is violated during the transcription or translation processes, the probability of reading a frameshifted stop codon is higher than if the code would have only one stop codon. Consequently, the synthesis of RNA or proteins will soon terminate. In this way, cells do not produce undesirable proteins and essentially save energy. This hypothesis is tested on the AT-rich Drosophila genome, where the detection of frameshifted stop codons is even higher than the theoretical value. Using the binomial theorem, we establish the probability of reading a frameshifted stop codon within n steps. Since the genetic code is largely redundant, there is still space for some hidden secondary functions of this code. In particular, because stop codons do not contain cytosine, random C → U and C → T mutations in the third position of codons increase the number of hidden frameshifted stops and simultaneously the same amino acids are coded. This evolutionary advantage is demonstrated on the genomes of several simple species, e.g. Escherichia coli.
机译:我们用三个终止密码子检查标准遗传密码。假设在转录或翻译过程中违反了DNA或RNA中长度3的同步周期,则读取移码终止密码子的可能性要比代码只有一个终止密码子的可能性高。因此,RNA或蛋白质的合成将很快终止。这样,细胞不会产生不希望的蛋白质并且实质上节省能量。该假设在富含AT的果蝇基因组上进行了检验,其中移码的终止密码子的检测率甚至高于理论值。使用二项式定理,我们建立了在n步内读取移码终止密码子的概率。由于遗传密码在很大程度上是多余的,因此该密码的一些隐藏的辅助功能仍然有空间。特别是,由于终止密码子不包含胞嘧啶,因此密码子第三位置的随机C→U和C→T突变会增加隐藏的移码终止子的数量,同时对相同的氨基酸进行编码。这种进化优势在几种简单物种的基因组上得到了证明,例如大肠杆菌。

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