首页> 外文期刊>Journal of the Chemical Society, Dalton Transactions. Inorganic Chemistry >Synthesis and reactions of dimethyltin dithiooxalate: a convenient dithiooxalate transfer reagent
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Synthesis and reactions of dimethyltin dithiooxalate: a convenient dithiooxalate transfer reagent

机译:二硫代草酸二甲基锡的合成与反应:一种方便的二硫代草酸转移剂

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摘要

Dimethyltin dithiooxalate has been synthesised by the reaction of dimethyltin dichloride with potassium dithiooxalate. It may be used as a dithiooxalate (dto) transfer reagent, reacting with [PtL_2Cl_2] [L_2 = 1,4-cyclooctadiene or 4,4'-bis(tert-butyl)-2,2'-bipyridine) to eliminate SnMe_2Cl_2 and form the corresponding platinum dithiooxalate compounds [Pt(COD)(dto)] 1 and [Pt(~tBu_2bipy)(dto)] 2. Reaction with the ruthenium compound [Ru(Me_2bipy)(PPh_3)_2Cl_2] 3 (Me_2bipy = 4,4'-dimethyl-2,2'-bipyridine) does not proceed analogously however, eliminating from the ruthenium one chloride and one triphenylphosphine ligand, and thus producing not SnMe_2Cl_2 but "[SnMe_2Cl]~+". This moiety becomes chelated within the dithiooxalate to produce the new 'Couccouvanis' type compound [cis-Ru(Me_2bipy)(PPh_3)Cl(mu-dto)(SnMe_2Cl)] 4. Reation of 4 with DMSO causes the elimination of SnMe_2Cl_2 by abstracting the tin centre and the second chloride ligand, producing cis-[Ru(Me_2bipy)(PPh_3)(DMSO)(dto)] 5. Upon treating 3 with [p-N ident to NC_6H_4F][BF_4] the oxidation product [Ru(Me_2bipy)(PPh_3)_2Cl_2][BF_4] 6 is formed. 6 reacts with SnMe_2(dto) to produce a bimetallic complex, [Ru(Me_2bipy)(PPh_3)_2(mu-dto)(SnMe_2Cl)][BF_4] 7a. The nature of the reduction products of 4 and 7 is explored, and the X-ray crystal structures of 2 and 5 are presented.
机译:通过二氯化二甲基锡与二硫代草酸钾的反应合成了二硫代草酸二甲基锡。它可以用作二硫代草酸酯(dto)转移试剂,与[PtL_2Cl_2] [L_2 = 1,4-环辛二烯或4,4'-双(叔丁基)-2,2'-联吡啶)反应以消除SnMe_2Cl_2和形成相应的二硫代草酸铂化合物[Pt(COD)(dto)] 1和[Pt(〜tBu_2bipy)(dto)]2。与钌化合物[Ru(Me_2bipy)(PPh_3)_2Cl_2] 3反应(Me_2bipy = 4,然而,4′-二甲基-2,2′-联吡啶没有类似地进行,从钌中除去了一种氯化物和一种三苯基膦配体,因此不产生SnMe_2Cl_2而是“ [SnMe_2Cl]〜+”。该部分在二硫代草酸酯中被螯合,产生新的“库库瓦尼”型化合物[顺式-Ru(Me_2bipy)(PPh_3)Cl(mu-dto)(SnMe_2Cl)]4。用DMSO还原4导致通过抽象去除SnMe_2Cl_2锡中心和第二个氯化物配体,产生顺式[Ru(Me_2bipy)(PPh_3)(DMSO)(dto)]5。用[pN与NC_6H_4F身份相同] [BF_4]处理3时,氧化产物[Ru(Me_2bipy)形成(PPh_3)_2Cl_2] [BF_4] 6。 6与SnMe_2(dto)反应生成双金属配合物[Ru(Me_2bipy)(PPh_3)_2(mu-dto)(SnMe_2Cl)] [BF_4] 7a。探索了4和7的还原产物的性质,并给出了2和5的X射线晶体结构。

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