首页> 外文期刊>Journal of the American Mathematical Society >EVEN GALOIS REPRESENTATIONSAND THE FONTAINE-MAZUR CONJECTURE.II
【24h】

EVEN GALOIS REPRESENTATIONSAND THE FONTAINE-MAZUR CONJECTURE.II

机译:甚至高卢瓦的代表和丰坦·马祖尔的假想II

获取原文
获取原文并翻译 | 示例
       

摘要

be a continuous irreducible representation unramified away from finitely many primes. In [FM95], Fontaine and Mazur conjecture that if p is semi-stable at p, then either p is the Tate twist of an even representation with finite image or p is modular. In [Kis09], Kisin establishes this conjecture in almost all cases under the additional hypotheses that p Dp has distinct Hodge—Tate weights and p is odd (see also [Eme]). The oddness condition in Kisin's work is required in order to invoke the work of Khare and Wintenberger [KWO9a, KW09b] on Serre's conjecture. If p is even and p > 2, however, then P will never be modular. Indeed, when p is even and p Dp has distinct Hodge-Tate weights. the conjecture of Fontaine and Mazur predicts that p does not exist. In [Cal 11], some progress was made towards proving this claim under the additional assumption that p was ordinary at p. The main result of this paper is to remove this condition. Up to conjugation, the image of p lands in GL_2(O), where O is the ring of integers of some finite extension L/Qp (see Lemme 2.2.1.1 of [BM02]). Let F denote the residue field, and let p : GQ→ GL_2(F) denote the corresponding residual representation. We prove:
机译:是一个连续的不可约表示,不受有限质数的影响。在[FM95]中,Fontaine和Mazur推测,如果p在p处是半稳定的,则p是具有有限图像的偶数表示的Tate扭曲,或者p是模数。在[Kis09]中,Kisin几乎在所有情况下均根据p Dp具有不同的Hodge-Tate权重且p为奇数的假设建立了这个猜想(另请参见[Eme])。为了引用Khare和Wintenberger [KWO9a,KW09b]关于Serre猜想的工作,需要Kisin工作中的奇数条件。但是,如果p为偶数且p> 2,则P将永远不是模数。实际上,当p为偶数且p Dp具有不同的Hodge-Tate权重时。 Fontaine和Mazur的猜想预测p不存在。在[Cal 11]中,在证明p在p处是普通的这一额外假设下,在证明这一主张方面取得了一些进展。本文的主要结果是消除了这种情况。直到共轭为止,p的图像落在GL_2(O)中,其中O是某个有限扩展L / Qp的整数环(请参阅[BM02]的引号2.2.1.1)。令F表示残差场,令p:GQ→GL_2(F)表示对应的残差表示。我们证明:

著录项

相似文献

  • 外文文献
  • 中文文献
  • 专利
获取原文

客服邮箱:kefu@zhangqiaokeyan.com

京公网安备:11010802029741号 ICP备案号:京ICP备15016152号-6 六维联合信息科技 (北京) 有限公司©版权所有
  • 客服微信

  • 服务号