首页> 外文期刊>Journal of Molecular Structure. Theochem: Applications of Theoretical Chemistry to Organic, Inorganic and Biological Problems >Ab initio study on the mechanism of forming a silapolycyclic compound between dimethylmethylenesilylene and acetone
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Ab initio study on the mechanism of forming a silapolycyclic compound between dimethylmethylenesilylene and acetone

机译:从头开始研究二甲基亚甲基亚甲硅烷基与丙酮之间形成硅多环化合物的机理

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The cycloaddition mechanism of forming a silapolycyclic compound between singlet dimethylmethylenesilylene and acetone has been investigated with MP2/6-31G* method, including geometry optimization and vibrational analysis for the involved stationary points on the potential energy surface. The energies of the different conformations are calculated with CCSD(T)/6-31G*//MP2/6-31G* method. From the potential energy profile, we predict that the cycloaddition reaction has two competitive dominant channels of forming a silapolycyclic compound. Both channels consist of four steps: (I) the two reactants first form three-membered ring intermediate and twisted four-membered ring intermediate through a barrier-free exothermic reactions of Delta E = -0.1 and -10.7 kJ mol(-1); (II) the three-membered ring intermediate and twisted four-membered ring intermediate then isomerize to two plane four-membered ring products via transition states with energy barriers of 3.4 and 6.5 kJ mol(-1); (III) the two plane four-membered ring products further react with acetone(R2) and form intermediates, which are also barrier-free exothermic reactions of Delta E = -38.9 and -64.8 kJ mol(-1); (IV) the two intermediates isomerize to silapolycyclic compounds via transition states with energy barriers of 41.8 and 45.9 kJ mol(-1), respectively.
机译:已通过MP2 / 6-31G *方法研究了在单线态二甲基亚甲基亚甲硅烷基与丙酮之间形成硅多环化合物的环加成机理,包括对势能表面上涉及的固定点进行几何优化和振动分析。不同构象的能量用CCSD(T)/ 6-31G * // MP2 / 6-31G *方法计算。根据势能曲线,我们预测环加成反应具有形成硅多环化合物的两个竞争性主导通道。这两个通道均包括四个步骤:(I)两种反应物首先通过Delta E = -0.1和-10.7 kJ mol(-1)的无障碍放热反应形成三元环中间体和扭曲的四元环中间体; (II)三元环中间体和扭曲的四元环中间体然后通过能级分别为3.4和6.5 kJ mol(-1)的过渡态异构化为两个平面四元环产物; (III)两个平面四元环产物进一步与丙酮(R2)反应并形成中间体,这也是Delta E = -38.9和-64.8 kJ mol(-1)的无障碍放热反应; (IV)两种中间体通过能级分别为41.8和45.9 kJ mol(-1)的过渡态异构化为多硅烷化合物。

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